How to Troubleshoot a Full-Wave Bridge Rectifier

It the situation described, there is no reactive power in the usual sense of reactive power. The harmonic currents cause reactive volt-amperers in the sense that little or no real power is transferred by the harmonic current. If the source voltage is a power frequency sine wave with only a little distortion, there is little or no source voltage at the harmonic frequencies. If current of one frequency is multiplied by a voltage of another frequency, there is no resulting real power. There is a periodic waveform containing both frequencies but the average of that waveform is zero.

In vector terms, if real power is on the X axis and reactive volt-amperes are on the Y axis, harmonic volt-amperes are on the Z axis. Harmonic volt-amperes are not the same as reactive-volt-amperes, the two can not be added algebraically.

I believe that the Q(VAR) data in your table is the square root of the sum of the squares of the RMS harmonic currents multiplied by the RMS voltage.

Have a look at:

http://www.circuitstoday.com/filter-circuits

Ripple Factor = Vac rms/Vdc = (√2/3)(Xc/XL) = (√2/3)(1/[2wc])(1/[2wL]) = 1/(6√2w2LC)