How to Match Transmission Line Impedance on Source Side

coaxialfpgaimpedance-matchingoscilloscopetransmission line

Suppose that I want to transmit a signal by a coaxial cable to a high-impedance load.

The signal is a single-ended TTL (3.3V) single square impulse from an FPGA output. The package of the FPGA is LQFP-144. The coaxial cable is a 50-ohm RG-174. The load is a high impedance input of an IC like an FPGA/MCU or an oscilloscope input with a 1Mohm internal load.

Also suppose that the FPGA output impedance is less than 50ohm. I have learned it from an IBIS model. Therefore in theory I can match an impedance with one series resistor on the source side.

But the 50-ohm line width on a 0.4mm FR4 is 0.73mm, and the pitch of the LQFP-144 is 0.5mm.

So, my impulse will run towards the load. Then it will reflect off and run to the 50-ohm connector on PCB, then it will reflect off from the connection of PCB line and 50-ohm connector despite any of my impedance matching actions.

Can I match a transmission line impedance on the source side in this case?

Best Answer

So, my impulse will run towards the load. Then it will reflect off and run to the 50-ohm connector on PCB, then it will reflect off from the connection of PCB line and 50-ohm connector despite any of my impedance matching actions.

Assuming the trace on the PCB is short compared to the rise-time (or fall-time) of the pulse, then very soon after the reflection between the connector and PCB line is generated, another reflection will be generated between the PCB line and the termination resistor you added at the source.

This second reflection will be (very nearly) equal and opposite the first reflection, so the total reflection onto the coaxial cable will be very small.

If this reflection is not acceptable, then you should re-design your PCB stack-up to allow you to make your PCB line \$Z_0\$ 50 ohms with a practical geometry.