How to treat the DC in calculate the time constant in RCL circuit having DC voltage source

circuit analysis

I want to ask that how to get the time constant for simple RCL circuit in order to get the natural response later, Here is the sample circuit. Assume that S is close at t=0 and the circuit is open for a long time

schematic

simulate this circuit – Schematic created using CircuitLab

when S close, in order to calculate the time constant \$\tau\$ in this case, I omit the source \$V_S\$ but then I don't know how the circuit which will be used to calculate \$\tau\$ look like. I thought \$V_S\$ will act like sort circuit so it'll look like this

schematic

simulate this circuit

but my lecturer said it actually looked like this, which doesn't have \$R_1\$

schematic

simulate this circuit

So what is the rule when omitting the source in case of: voltage source and voltage source. What if the switch is in series but not parallel?

Best Answer

I thought \$V_S\$ will act like short circuit

This is why you're confused.

In this circuit, we don't have any control over \$V_S\$ - it is a constant, unchanging, DC voltage. However, we do have control over the switch in the circuit. When, we close the switch, the circuit splits into two separate pieces.

The left side of the circuit becomes:

schematic

simulate this circuit – Schematic created using CircuitLab

Since this circuit has nothing to do with the inductor, we can ignore it.

The right side of the circuit is what your teacher drew, so we can simply analyze that on its own. Note that \$V_S\$ hasn't changed - instead, we've totally taken it out of the circuit.