Power Supply – Mean Well Power Supplies Efficiency and Leakage Current Issues

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I am going to have a power supply which will always be connected to AC mains and occasionally, a led strip will be connected and disconnected to the supply with a relay. I want an efficient and low "no Load" power supply. The two power supplies I've bought are below:

1. Mean Well RS-25-12: efficiency 81.5% | LEAKAGE CURRENT < 2mA / 240VAC (aka no Load power < 0.5W) | RS-25 datasheet

2. Mean Well LRS-35-12: efficiency 86% | LEAKAGE CURRENT < 0.75mA / 240VAC (aka no Load power < 0.2W) | LRS-35 datasheet

I made some tests with my UT89X multimeter when they arrived. I used different lengths of the same LED strip as loads when calculating Pout and Pin that's why output current differs but this is not important now. My results are below:

Mean Well RS-25-12:
Pin_noLoad = 224V * 0.034A = 7.62VA |
Pout_Loaded = 12V * 1.46A = 17.52W |
Pin_Loaded = 224V * 0.170 = 38.08VA |
eff = %46

Mean Well LRS-35-12:
Pin_noLoad = 224V * 0.046A = 10.3 |
Pout_Loaded = 12.08V * 1.21A = 14.6W |
Pin_Loaded = 224V * 0.245A = 54.88VA |
eff = %26.6

Terrible performance. Even a 2.2 dollars power supply outperform them, the result for the cheap power supply is below:

CATA 60W:
Pin_noLoad: 224V * 0.0082A = 1.84VA |
Pout_Loaded = 10V * 1A = 10W |
Pin_Loaded = 224V * 0.112A = 25VA |
eff = %40

The output voltage dropped from 12V to 10V as the cheap power supply is loaded but that's not the point.

I've used alternating and direct current and voltage settings on the mulltimeter as needed during my test. I didn't consider the power factor in my calculations as I didn't know the value but I think it will make the results only slightly better. Is my method of test wrong? Is Mean Well a very bad brand? Am I being sold fake brand power supplies even though the sellers are relatively trustworthy?

I bought each RS-25-12 and LRS-35-12 for 12.5 dollars.

ENLIGHTENMENT EDIT (Solution):
I assumed power factor would be a constant value around 0.8 ~ 0.9 But in reality it fluctuates between 0 and max value depending on the load. Thus my VA measurements doesn't mean anything on behalf of efficiency. Sorry Mean Well 😀

Best Answer

There are two reasons for the gap between the datasheets and your expectations.

  • "Leakage current" refers to leakage from L-E (primarily due to filter capacitors), not zero load supply current.

  • Your measurements are giving you VA not power, and small supplies such as these often have very bad power factors at anything other than full rated load (unless they explicitly quote a PF nearer 0.98, in which case they have active PFC).

You need to use a watt meter to determine actual efficiency.

If you are not convinced, think about the heat from a 40W light bulb, and then decide if this is the amount of heat coming out of your LRS35 unit when you are quoting 26% efficiency (as the other 74% would have to be going as heat if your interpretation was right).