PIC18f8722 interrupt problem

interruptspic

I did many research but couldn't find out what the problem it is. Actually my code as below. I am trying to implement a code in C with XC8 compiler.

To enable a sentence on the LCD of the board while RB6 button is pressed. I enable INCTONbits.GIE = 1 and INTCONbits.RBIE = 1 and INTCONbits.RBIF = 0.

Inside of interrupt, the displaySentence() function is entered to infinity loop to see result. I checked all answers related with interrupt in here but didn't help my problem. What can be problem for RB7-4 interrupt, I am working on PIC18f8722.

void displaySentence();

void initialize();


void interrupt  RBINT_ISR(void){

    INTCONbits.GIE = 0;

 __delay_ms(10);

    while(1){
        displaySentence();
    }
    INTCONbits.RBIF = 0;
    INTCONbits.RBIE = 1;
    INTCONbits.GIE = 1;
}


void main(void)
{
    __delay_ms(15);
    __delay_ms(15);
    __delay_ms(15);
    __delay_ms(15);

    InitLCD();          // Initialize LCD in 4bit mode
    ClearLCDScreen();  // Clear LCD screen

    initialize();

    while(1);
}



void initialize(){

    TRISB = 0x40;
    PORTB = 0x00;

    // | GIE/GIEH | PEIE/GIEL | TMR0IE  | INT0IE | RBIE | TMR0IF | INT0IF | RBIF
    // |   1      |    0      |  0      |  0     |   1  |   0    |    0   |  0
    INTCONbits.RBIF = 0;
    INTCONbits.RBIE = 1;
    INTCONbits.GIE = 1;
}

void displaySentence(){

    WriteCommandToLCD(0x80);
    WriteStringToLCD("Interrupt");
    WriteCommandToLCD(0xC0);
    WriteStringToLCD("is working");
}

Best Answer

Thanks @brhans for your answer I did as you said. I disabled INTCON2bits.RBPU = 0 and it worked for me.

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