There's no such thing as "lossless" anything in electronics, and there's not a single IC that's designed to do what you want. But here are some different supply ideas. Since you didn't specify current consumption or efficiency, let's look at three different approaches:
Non-isolating Zener supply
5% efficiency or less
Plug-in timers that are microcontroller-based usually use non-isolating power supplies, like this:
R1 essentially drops the difference between the Zener diode and the AC mains potential, so it's not going to be efficient for anything except light loads. Also, your load can't change dramatically, as the resistor has to be sized to provide enough current to the zener to cause it to reverse avalanche, without providing too much current. If your load starts pulling too much current, its voltage will drop. If your load doesn't pull enough current, the zener diode can be damaged.
Pros
- Very small
- Very cheap
- Excellent for extremely light loads (MCU + switch device)
Cons
- No isolation
- Load current isn't flexible; must be fixed within small window
Mains-frequency regulated transformer supply
20-75% efficiency
You can always use a transformer (60:1 or so), a bridge rectifier, and a linear regulator, like this:
This introduces a bulky, costly transformer into the design, but it's more efficient than the previous design, and your load can vary quite a bit.
Pros
- Easiest to implement
- Designed for medium current loads -- a clock radio, for example.
- Full isolation
- Relatively inexpensive
Cons
Fully-isolated Switch-mode AC/DC Converter
75-95% efficiency
Most efficient (and most complex) is a AC/DC switching converter. These work on the principle of first converting AC to DC, then switching the DC at very high frequencies to make optimal use of the transformer's characteristics, as well as minimize the size (and loss) of the filter network on the secondary. Power Integrations makes an IC that does all the control/feedback/driving -- all you need is to add a transformer and optoisolators. Here's an example design:
As you can see, AC mains voltage is immediately rectified and filtered to produce high voltage DC. The Power Integrations device switches this voltage rapidly across the transformer's primary side. High-frequency AC is seen on the secondary, and rectified and filtered. You'll notice that the component values are quite small, even considering the current use. This is because high-frequency AC requires much smaller components to filter than line-frequency AC. Most of these devices have special ultra-low-power modes that work quite well.
These converters, in general, provide a great amount of efficiency and can also source high-power loads. These are the sorts of supplies you see in everything from tiny cell phone chargers to laptop and desktop computer power supplies.
Pros
- Extremely Efficient
- Full isolation
- High output current: can source 50+ amps of low voltage DC fairly easily.
- Small size
Cons
- Large BOM (Bill of Materials)
- Difficult to design
- Requires thoughtful PCB layout
- Usually requires custom transformer design
- Expensive
In North America, an electric stove will normally have a dedicated 120/240 volt circuit with a 50 Amp two-pole circuit breaker. Electric stoves are not intended to be operated from a single 120 volt circuit.
A stove (range) outlet looks like:
Best Answer
Look at my answer (LINK) to a similar question. When operating at a lower frequency, an induction motor must be operated at a proportionally lower voltage. For a motor rated 110V, 60Hz, you need 92V 50Hz. If you uses an electronic converter that has a 110V, 60Hz output, that will be ok, but the converter needs to supply a higher current for a half second or so while the motor is starting and accelerating to full speed. The starting current could be something like six times the normal current. An electronic converter will not be very tolerant of even a fraction of a second of excess current. You may be able to find an electronic converter that has specifications that state that is suitable for starting a motor of a stated power rating.
A tranformer will be more tolerant of a brief current surge, but it will not convert the frequency from 50Hz to 60Hz. For your motor, the transformer voltage needs to be 92 volts rather than 110. Even though it will be tolerant of the starting current, the voltage will drop during the current surge, so it would still be best to select a larger size than needed for rated motor current.
Edit:
Another concern for 50Hz operation of a single-phase, capacitor-start motor is that the speed at 50Hz might not be high enough to operate the centrifugal switch that disconnects the capacitor when the motor reaches full speed when starting.