In the following question on symmetrical components, the 11kV of the source is the line-to-line voltage. When using symmetrical components you want to be working with line-to-neutral voltage. Am I right in saying this? In the memo for this question the 11kV is devided by squareroot 3 in order to obtain the phase voltages. Initially I used the 11kV without dividing by squareroot 3. How would I determine which path to follow (divide or not by squareroot 3), by looking at this question? Is there a standard which I should always follow, or am I missing key words in the question which tells me exactly what to do?
I am fine with the rest of the question, I'm just confused in determining the phase voltages. Thank you
"A 11 kV source delivers power to a power
system with terminal voltages at rated value.
A fault occurs in the source and it causes the
b-phase voltage Vbn of the source to fall to
zero (not an open circuit). With the a-phase
voltage Van of the source as the zero
reference, calculate the sequence network
voltages V0, V1 and V2."
Best Answer
Usually when talking about 3 phase machines, the voltage is indicated by line to line. It is easy to remember this because the terminals that are accessible by the operator are a, b, and c. So a measured or applied voltage would only be between a-b, b-c, or a-c. Which is line to line.