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If the current flows counterclockwise, the current source becomes invalid but if it flows clockwise the voltage source becomes invalid? So what would happen?
What would happen in this circuit
circuit analysis
Related Solutions
The way this is drawn R2 does nothing. When the switch is off (as drawn) nothing happens the circuit is incomplete.
When the switch is on you will charge the capacitor until it is fully charged and current will stop flowing. R1 and R2 simply sum to 1 equivalent resistor R. And the charge profile will look like this:
Source: http://hyperphysics.phy-astr.gsu.edu/hbase/electric/capchg.html
In circuit 1 you get infinite voltages and in circuit 2 you get zero current.
EDIT due to wrong circuit posted in question - circuit 2 takes 45mA and I'm not inclined to feed the reasons on a plate to the OP because this sort of stuff should be reasoned through.
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Best Answer
You seem to think that you have created a problem, but not in this case. The 1A will flow through current source, there will be 1V across the voltage source. The current source will have the voltage over it that makes this happen, likewise the voltage source will have the current through it to make this happen (which must be 1A).
1A flows through the resistor too. Let's (arbitrarily) define its lefts side as 0V, then its right side must be at +100V, hence the voltage over the current source is 99V.
If you invert the current source the right side of the resistor is at -100V, hence the voltage over the current source is -101V.
Note that voltage sources and current sources are theoretical constructs, just like a line, circle and point. You can create 'impossible' diagrams with them, for instance a shorted voltage source or an open current source, or voltage sources for different voltages in parallel. It makes no sense to ask 'what would happen in such a case' because those idealized components do not exist. We can calculate with them within certain restrictions, outside those restrictions we can't calculate with them. That's all.