I want to call a static block into another static block if the right conditions are met. I believe that my main problem is how to register the template in XML, as I never worked with it before.
First off I have a static block with the code: footer02-links.
Here I'm trying to call my template file. I realise that the code below is missing the XML tags.
{{block template="custom/employee-links-template.phtml"}}
Then in the themes template folder in /custom/employee-links-template.phtml I have my conditional statement.
<?php if (Mage::getSingleton('customer/session')->isLoggedIn() && Mage::getSingleton('customer/session')->getCustomerGroupId() == "4") :?>
<?php echo $this->getChildHtml('employee-links') ?>
<?php endif;?>
So if the customer is logged in and part of customer group with ID 4, they will be shown the static block with the code: employee-links.
In this static block I simply have a link to a otherwise hidden category.
<li><a title="Employee Offers" href="/employee-offers.phtml">Employee Monthly Offers</a></li>
So I guess my problem is how to register the block in the local.xml file, which I really have no idea of how to do. Furthermore there might be a better way to do what I'm trying to achieve?
Best Answer
First off, the code should be
No need to edit your local.xml you can call your static block in your
custom/employee-links-template.phtml
template, see below.Explanation: You cannot add children to blocks that are dynamically created with
{{block}}
, or access them from the layout XML, so you have to create the inner block directly from the template.