I stored some data in database. I want to function my program in such a way that when I click on an edit link whole data gets extracted from database and get displayed on a form.
When I click on 1st row edit button its corresponding data must get displayed in the above form.
The given below is my code for form and table.
<form role="form" action="<?php echo $this->getUrl('test/user_view/save'); ?>" method="post">
<div id="form_div">
<label>Title</label>
<input id="title" type="text" name="title" />
<br /><br />
<label>File Name</label>
<input id="file_name" type="text" name="filename" />
<br /><br />
<label>Content</label>
<input id="content" type="text" name="content" />
<br /><br />
<label>Status</label>
<input id="status" type="text" name="status" />
<br /><br />
<input id="add_button" type="submit" value="Add" />
</div>
<br /><br />
</form>
<form role="form" action="<?php echo $this->getUrl('test/user_view/edit'); ?>" method="post">
<table border="">
<tr>
<th>Test_Id</th>
<th>Title</th>
<th>File Name</th>
<th>Content</th>
<th>Status</th>
<th>Created Time</th>
<th>Updated Time</th>
<th>Edit</th>
<th>Delete</th>
</tr>
<?php
$model = Mage::getModel('test/test')->getCollection();
foreach($model as $data)
{
echo '<tr>';
echo '<td>'.$data->getTestId().'</td>';
echo '<td>'.$data->getTitle().'</td>';
echo '<td>'.$data->getFilename().'</td>';
echo '<td>'.$data->getContent().'</td>';
echo '<td>'.$data->getStatus().'</td>';
echo '<td>'.$data->getCreatedTime().'</td>';
echo '<td>'.$data->getUpdateTime().'</td>';
?>
<td><a id="edit">Edit</a></td>
<td><a href='?id=<?php echo $data->getTestId() ?>'>Delete</a></td>
<?php
echo '</tr>';
}
?>
</table>
</form>
Best Answer
Through Ajax you can get data from database in the following way:
First send the Ajax request with id parameter through onClick() event of edit link as shown below:
Then write the getData() function to send the ajax request as shown below: