Based on their understanding of the Fast Retransmit algorithm, I believe the authors are giving you their real-world idea of what to expect. Understand, this is the authors' idea. Even your argument is made with some assumptions which may, or may not, be congruent with the authors' assumptions. You could contact the authors for clarification. A simple search turns up a verified e-mail address for Larry Peterson at the University of Arizona.
3.2 Fast Retransmit/Fast Recovery
A TCP receiver SHOULD send an immediate duplicate ACK when an out-
of-order segment arrives. The purpose of this ACK is to inform the
sender that a segment was received out-of-order and which sequence
number is expected. From the sender's perspective, duplicate ACKs
can be caused by a number of network problems. First, they can be
caused by dropped segments. In this case, all segments after the
dropped segment will trigger duplicate ACKs. Second, duplicate ACKs
can be caused by the re-ordering of data segments by the network (not
a rare event along some network paths [Pax97]). Finally, duplicate
ACKs can be caused by replication of ACK or data segments by the
network. In addition, a TCP receiver SHOULD send an immediate ACK
when the incoming segment fills in all or part of a gap in the
sequence space. This will generate more timely information for a
sender recovering from a loss through a retransmission timeout, a
fast retransmit, or an experimental loss recovery algorithm, such as
NewReno [FH98].
The TCP sender SHOULD use the "fast retransmit" algorithm to detect
and repair loss, based on incoming duplicate ACKs. The fast
retransmit algorithm uses the arrival of 3 duplicate ACKs (4
identical ACKs without the arrival of any other intervening packets)
as an indication that a segment has been lost. After receiving 3
duplicate ACKs, TCP performs a retransmission of what appears to be
the missing segment, without waiting for the retransmission timer to
expire.
After the fast retransmit algorithm sends what appears to be the
missing segment, the "fast recovery" algorithm governs the
transmission of new data until a non-duplicate ACK arrives. The
reason for not performing slow start is that the receipt of the
duplicate ACKs not only indicates that a segment has been lost, but
also that segments are most likely leaving the network (although a
massive segment duplication by the network can invalidate this
conclusion). In other words, since the receiver can only generate a
duplicate ACK when a segment has arrived, that segment has left the
network and is in the receiver's buffer, so we know it is no longer
consuming network resources. Furthermore, since the ACK "clock"
[Jac88] is preserved, the TCP sender can continue to transmit new
segments (although transmission must continue using a reduced cwnd).
The fast retransmit and fast recovery algorithms are usually
implemented together as follows.
When the third duplicate ACK is received, set ssthresh to no more
than the value given in equation 3.
Retransmit the lost segment and set cwnd to ssthresh plus 3*SMSS.
This artificially "inflates" the congestion window by the number
of segments (three) that have left the network and which the
receiver has buffered.
For each additional duplicate ACK received, increment cwnd by
SMSS. This artificially inflates the congestion window in order
to reflect the additional segment that has left the network.
Transmit a segment, if allowed by the new value of cwnd and the
receiver's advertised window.
When the next ACK arrives that acknowledges new data, set cwnd to
ssthresh (the value set in step 1). This is termed "deflating"
the window.
This ACK should be the acknowledgment elicited by the
retransmission from step 1, one RTT after the retransmission
(though it may arrive sooner in the presence of significant out-
of-order delivery of data segments at the receiver).
Additionally, this ACK should acknowledge all the intermediate
segments sent between the lost segment and the receipt of the
third duplicate ACK, if none of these were lost.
Note: This algorithm is known to generally not recover very
efficiently from multiple losses in a single flight of packets [FF96].
One proposed set of modifications to address this problem can be found
in [FH98].
Best Answer
Segmentation (or rather fragmentation)
Although in some literature you may find the term
segmentation
to refer to the process of dividing an IP packet that is bigger than theMaximum Transfer Unit
(MTU) of the link, the correct term isfragmentation
.See @adam86 answer for what segmentation refers to.
Switching
Switching is totally different, it refers to the process, performed by devices commonly known as
switch
, although the official term ismac bridge
, which transfer (unchanged), an Ethernet frame from a LAN to another LAN.Mac bridges are defined by the IEEE standard 802.1D
In modern Ethernet networking, switching is performed when a switch receives an Ethernet frame on one of its ports and transfers it to another port on which the receiver is attached.
The switch use the destination MAC address present in the Ethernet frame to select the port to send the frame to.
The term "switching" come from the fact the frame is recopied from one port to another one, by opposition with older hubs which send the frame to all ports (except the one on which the frame was received).