Centos – suexec error configuring mod_fastcgi with apache2.2.3 on centos

apache-2.2centosfastcgiPHPsuexec

I've been following this blog post so that I can share APC opcode cache between PHP processes using FastCGI. Unfortunately I'm getting the following error when starting httpd:

Starting httpd: Syntax error on line 4 of /etc/httpd/conf.d/mod_fastcgi.conf:
FastCgiWrapper: "/usr/sbin/suexec" execute access for server (uid -1, gid -1) failed: execute not allowed

Line 4 of mod_fastcgi.conf has FastCgiWrapper On. I notice that the documentation states that this line could specify the path to the wrapper. Should that be changed?

I've checked that the permissions of the user's php-fastcgi script (550) and directory (555) are correct, /usr/sbin/suexec is correct (-r-s--x---) and that suEXEC is being loaded by apache ([notice] suEXEC mechanism enabled (wrapper: /usr/sbin/suexec)).

Where else should I be looking? I'm pretty sure that this is a permissions or path issue…

TIA,
JD

Best Answer

It's to do with the order of the directives. In conf/http.conf it includes conf.d/* before it specifies User and Group directives.

Try putting mod_fastcgi.conf in conf/ and at the end of httpd.conf append

Include conf/mod_fastcgi.conf

Related Solutions

Centos – Installing Apache MPM Worker on Centos 5.5

On my system I just edited the /etc/sysconfig/httpd file to enable the httpd.worker.

After restarting httpd, I ran "ps -ef | grep -i http" and got this:

[root@localhost httpd]# ps -ef | grep -i http
root     16334 17289  0 10:44 pts/1    00:00:00 grep -i http
root     30536     1  0 10:00 ?        00:00:00 /usr/sbin/httpd.worker
apache   30539 30536  0 10:00 ?        00:00:00 /usr/sbin/httpd.worker
apache   30541 30536  0 10:00 ?        00:00:02 /usr/sbin/httpd.worker
[root@localhost httpd]#

If I switch the /etc/sysconfig/httpd back to the default, the ps output is like this:

[root@localhost httpd]# ps -ef | grep -i http
root     16447     1  0 10:47 ?        00:00:00 /usr/sbin/httpd
apache   16448 16447  0 10:47 ?        00:00:00 /usr/sbin/httpd
apache   16449 16447  0 10:47 ?        00:00:00 /usr/sbin/httpd
apache   16450 16447  0 10:47 ?        00:00:00 /usr/sbin/httpd
apache   16451 16447  0 10:47 ?        00:00:00 /usr/sbin/httpd
apache   16453 16447  0 10:47 ?        00:00:00 /usr/sbin/httpd
apache   16454 16447  0 10:47 ?        00:00:00 /usr/sbin/httpd
apache   16455 16447  0 10:47 ?        00:00:00 /usr/sbin/httpd
apache   16456 16447  0 10:47 ?        00:00:00 /usr/sbin/httpd
root     16458 17289  0 10:47 pts/1    00:00:00 grep -i http
[root@localhost httpd]#

And in this case the "httpd -V" output is the same as before.

Since the number of running processes matches my configuration options for the prefork and worker modules set in the "/etc/httpd/conf/httpd.conf" I believe it's working as advertised.

I suspect the "httpd -V" is reporting the compiled in defaults. because: server binary names are different. httpd (prefork,default) != httpd.worker (non-default)

Dan

Php – Single fastcgi/php-cgi server for multiple virtualhosts

If i may add a personal opinion..

Use Nginx, its faster, simpler, and much easier to do what you want.. ( and uses much less memory )

Its a personal preference of mine.. :D

https://calomel.org/nginx.html is a nice detailed example

Best Answer

Related Solutions

Centos – Installing Apache MPM Worker on Centos 5.5

Php – Single fastcgi/php-cgi server for multiple virtualhosts

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