Freebsd – How to find a file that contains the specified string in FreeBSD

I'd use Python for this. Put all this code into a file called mass_replace and "chmod +x mass_replace":

#!/usr/bin/python

import os
import re
import sys

def file_replace(fname, s_before, s_after):
    out_fname = fname + ".tmp"
    out = open(out_fname, "w")
    for line in open(fname):
        out.write(re.sub(s_before, s_after, line))
    out.close()
    os.rename(out_fname, fname)


def mass_replace(dir_name, s_before, s_after):
    for dirpath, dirnames, filenames in os.walk(dir_name):
        for fname in filenames:
            f = fname.lower()
            # example: limit replace to .txt, .c, and .h files
            if f.endswith(".txt") or f.endswith(".c") or f.endswith(".h"):
                f = os.path.join(dirpath, fname)
                file_replace(f, s_before, s_after)

if len(sys.argv) != 4:
    u = "Usage: mass_replace <dir_name> <string_before> <string_after>\n"
    sys.stderr.write(u)
    sys.exit(1)

mass_replace(sys.argv[1], sys.argv[2], sys.argv[3])

For a single search and replace of one string in one type of file, the solution with find and sed isn't bad. But if you want to do a lot of processing in one pass, you can edit this program to extend it, and it will be easy (and likely to be correct the first time).

This would be my approach:

find dev -type f -print0 | \          # find all files
xargs -0 grep 'extends MY_Output' | \ # search for your string
cut -d/ -f2  | \                      # extract web folder name
sort | uniq                           # eliminate duplicates

Note use of the print0 parameter to find and the -0 (zero) flag to xargs, which prevents problems if your filenames have embedded spaces in them.