I have a server with 8x SAS drives attached to hardware LSI RAID controller (MegaCli64) and all 8 drives are configured as single RAID 10 array.
I now want to remove 2 drives and replace them with bigger drives.
Result should be one RAID 10 array of 6 drives and second RAID 1 array of 2 drives.
OS : CentOS 6
How can I reduce LSI raid array and remove 2 drives without data loss so that 2 drives could be removed? Server downtime is no problem.
From Google I see that MegaCli64 -LDRecon could help but I have never used it and don't have a test server at present to experiment.
UPDATE 1
[root@n ~]# df -h
Filesystem Size Used Avail Use% Mounted on
/dev/sda2 49G 8.9G 37G 20% /
/dev/sda5 2.1T 1.6T 457G 78% /backup
/dev/sda1 388M 93M 275M 26% /boot
All drives are of type ext4 in Linux.
/backup is not important, I can easily copy data and copy it back but I certainly do not want to reinstall OS and all configurations and setups of various softwares. It would demand too much time.
UPDATE 2
All current disks (8 in number) are of 600GB in size type SCSI 15k RPM. I want to replace 2 drives with new 4TB drives type SATA 7K RPM.
This is an Supermicro F627R3-R72B+ server with LSI 2208 controller.
Best Answer
You can't do this. You can only remove one disk at a time using the
-LDRecon Rmv
switch, and given the scale of drives you're speaking about, this would probably be the most complex path you could possibly take to get where you want.On the HP ProLiant Smart Array side of things, shrinking of LogicalDrives is a very new feature, and even then, it's not a recommended approach.