batch-filecommand-line-interfacewindowswindows 7
I want to send a path as an argument to an executable.
what I want to do something like this:
pushd some\folder
set x=cd
popd
MyExe.exe %x%
the problem is that the x variable is now equal to the string "cd" but what I want is to get the output of cd into x.
How do I do that?
I've had success with Sysinternals Process Explorer. With this, you can search to find what process(es) have a file open, and you can use it to close the handle(s) if you want. Of course, it is safer to close the whole process. Exercise caution and judgement.
To find a specific file, use the menu option Find->Find Handle or DLL... Type in part of the path to the file. The list of processes will appear below.
If you prefer command line, Sysinternals suite includes command line tool Handle, that lists open handles.
Examples
c:\Program Files\SysinternalsSuite>handle.exe |findstr /i "e:\" (finds all files opened from drive e:\"c:\Program Files\SysinternalsSuite>handle.exe |findstr /i "file-or-path-in-question"
Best Answer
Windows maintains the current directory in the environment variable
%CD%.will pass c:\temp to MyExe.exe