C++ – How to check symbols in C++

cif statement

I'm beginner in programming (specially in C++). I've tried to check incoming symbols for letters. I need to "catch" only numbers from 0 to 9. So, i try to use it:

// Checking "a". If "a" is a letter, the error must be printed;
if (a!='%d') {
    cout << "pfff! U cant use letters!" << endl;
    return -1;
}
// The end of checking;

But it doesn't work. I guess that i can't use '%d' in C++. How i can say:
"Check all symbols and stop the program if there will be non-numbers."

P.S. Sorry for my english. I hope u got me.

Best Answer

Yes , isdigit() will work out nicely here .

An example is :

    #inlude <iostream>
    #include <ctype.h>
    // in ctype.h is located the isdigit() function
    using namespace std;
    //...
    char test;
    int x;
    cin >> test;
    if ( isdigit(test) )//tests wether test is == to '0', '1', '2' ...
    {
          cin>>putback(test);//puts test back to the stream
          cin >> x;
    }
    else
         errorMsg();

Related Solutions

C++ – How to list the symbols in a .so file

The standard tool for listing symbols is nm, you can use it simply like this:

nm -gD yourLib.so

If you want to see symbols of a C++ library, add the "-C" option which demangle the symbols (it's far more readable demangled).

nm -gDC yourLib.so

If your .so file is in elf format, you have two options:

Either objdump (-C is also useful for demangling C++):

$ objdump -TC libz.so

libz.so:     file format elf64-x86-64

DYNAMIC SYMBOL TABLE:
0000000000002010 l    d  .init  0000000000000000              .init
0000000000000000      DF *UND*  0000000000000000  GLIBC_2.2.5 free
0000000000000000      DF *UND*  0000000000000000  GLIBC_2.2.5 __errno_location
0000000000000000  w   D  *UND*  0000000000000000              _ITM_deregisterTMCloneTable

Or use readelf:

$ readelf -Ws libz.so
Symbol table '.dynsym' contains 112 entries:
   Num:    Value          Size Type    Bind   Vis      Ndx Name
     0: 0000000000000000     0 NOTYPE  LOCAL  DEFAULT  UND
     1: 0000000000002010     0 SECTION LOCAL  DEFAULT   10
     2: 0000000000000000     0 FUNC    GLOBAL DEFAULT  UND free@GLIBC_2.2.5 (14)
     3: 0000000000000000     0 FUNC    GLOBAL DEFAULT  UND __errno_location@GLIBC_2.2.5 (14)
     4: 0000000000000000     0 NOTYPE  WEAK   DEFAULT  UND _ITM_deregisterTMCloneTable

C++ – How to set, clear, and toggle a single bit

Setting a bit

Use the bitwise OR operator (|) to set a bit.

number |= 1UL << n;

That will set the nth bit of number. n should be zero, if you want to set the 1st bit and so on upto n-1, if you want to set the nth bit.

Use 1ULL if number is wider than unsigned long; promotion of 1UL << n doesn't happen until after evaluating 1UL << n where it's undefined behaviour to shift by more than the width of a long. The same applies to all the rest of the examples.

Clearing a bit

Use the bitwise AND operator (&) to clear a bit.

number &= ~(1UL << n);

That will clear the nth bit of number. You must invert the bit string with the bitwise NOT operator (~), then AND it.

Toggling a bit

The XOR operator (^) can be used to toggle a bit.

number ^= 1UL << n;

That will toggle the nth bit of number.

Checking a bit

You didn't ask for this, but I might as well add it.

To check a bit, shift the number n to the right, then bitwise AND it:

bit = (number >> n) & 1U;

That will put the value of the nth bit of number into the variable bit.

Changing the nth bit to x

Setting the nth bit to either 1 or 0 can be achieved with the following on a 2's complement C++ implementation:

number ^= (-x ^ number) & (1UL << n);

Bit n will be set if x is 1, and cleared if x is 0. If x has some other value, you get garbage. x = !!x will booleanize it to 0 or 1.

To make this independent of 2's complement negation behaviour (where -1 has all bits set, unlike on a 1's complement or sign/magnitude C++ implementation), use unsigned negation.

number ^= (-(unsigned long)x ^ number) & (1UL << n);

unsigned long newbit = !!x;    // Also booleanize to force 0 or 1
number ^= (-newbit ^ number) & (1UL << n);

It's generally a good idea to use unsigned types for portable bit manipulation.

number = (number & ~(1UL << n)) | (x << n);

(number & ~(1UL << n)) will clear the nth bit and (x << n) will set the nth bit to x.

It's also generally a good idea to not to copy/paste code in general and so many people use preprocessor macros (like the community wiki answer further down) or some sort of encapsulation.