What exactly does it mean if a function is defined as virtual and is that the same as pure virtual?
C++ – Virtual/pure virtual explained
cvirtual
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The compiler is allowed to make one implicit conversion to resolve the parameters to a function. What this means is that the compiler can use constructors callable with a single parameter to convert from one type to another in order to get the right type for a parameter.
Here's an example class with a constructor that can be used for implicit conversions:
class Foo
{
public:
// single parameter constructor, can be used as an implicit conversion
Foo (int foo) : m_foo (foo)
{
}
int GetFoo () { return m_foo; }
private:
int m_foo;
};
Here's a simple function that takes a Foo
object:
void DoBar (Foo foo)
{
int i = foo.GetFoo ();
}
and here's where the DoBar
function is called:
int main ()
{
DoBar (42);
}
The argument is not a Foo
object, but an int
. However, there exists a constructor for Foo
that takes an int
so this constructor can be used to convert the parameter to the correct type.
The compiler is allowed to do this once for each parameter.
Prefixing the explicit
keyword to the constructor prevents the compiler from using that constructor for implicit conversions. Adding it to the above class will create a compiler error at the function call DoBar (42)
. It is now necessary to call for conversion explicitly with DoBar (Foo (42))
The reason you might want to do this is to avoid accidental construction that can hide bugs.
Contrived example:
- You have a
MyString
class with a constructor that constructs a string of the given size. You have a functionprint(const MyString&)
(as well as an overloadprint (char *string)
), and you callprint(3)
(when you actually intended to callprint("3")
). You expect it to print "3", but it prints an empty string of length 3 instead.
static_cast
is the first cast you should attempt to use. It does things like implicit conversions between types (such as int
to float
, or pointer to void*
), and it can also call explicit conversion functions (or implicit ones). In many cases, explicitly stating static_cast
isn't necessary, but it's important to note that the T(something)
syntax is equivalent to (T)something
and should be avoided (more on that later). A T(something, something_else)
is safe, however, and guaranteed to call the constructor.
static_cast
can also cast through inheritance hierarchies. It is unnecessary when casting upwards (towards a base class), but when casting downwards it can be used as long as it doesn't cast through virtual
inheritance. It does not do checking, however, and it is undefined behavior to static_cast
down a hierarchy to a type that isn't actually the type of the object.
const_cast
can be used to remove or add const
to a variable; no other C++ cast is capable of removing it (not even reinterpret_cast
). It is important to note that modifying a formerly const
value is only undefined if the original variable is const
; if you use it to take the const
off a reference to something that wasn't declared with const
, it is safe. This can be useful when overloading member functions based on const
, for instance. It can also be used to add const
to an object, such as to call a member function overload.
const_cast
also works similarly on volatile
, though that's less common.
dynamic_cast
is exclusively used for handling polymorphism. You can cast a pointer or reference to any polymorphic type to any other class type (a polymorphic type has at least one virtual function, declared or inherited). You can use it for more than just casting downwards – you can cast sideways or even up another chain. The dynamic_cast
will seek out the desired object and return it if possible. If it can't, it will return nullptr
in the case of a pointer, or throw std::bad_cast
in the case of a reference.
dynamic_cast
has some limitations, though. It doesn't work if there are multiple objects of the same type in the inheritance hierarchy (the so-called 'dreaded diamond') and you aren't using virtual
inheritance. It also can only go through public inheritance - it will always fail to travel through protected
or private
inheritance. This is rarely an issue, however, as such forms of inheritance are rare.
reinterpret_cast
is the most dangerous cast, and should be used very sparingly. It turns one type directly into another — such as casting the value from one pointer to another, or storing a pointer in an int
, or all sorts of other nasty things. Largely, the only guarantee you get with reinterpret_cast
is that normally if you cast the result back to the original type, you will get the exact same value (but not if the intermediate type is smaller than the original type). There are a number of conversions that reinterpret_cast
cannot do, too. It's used primarily for particularly weird conversions and bit manipulations, like turning a raw data stream into actual data, or storing data in the low bits of a pointer to aligned data.
C-style cast and function-style cast are casts using (type)object
or type(object)
, respectively, and are functionally equivalent. They are defined as the first of the following which succeeds:
const_cast
static_cast
(though ignoring access restrictions)static_cast
(see above), thenconst_cast
reinterpret_cast
reinterpret_cast
, thenconst_cast
It can therefore be used as a replacement for other casts in some instances, but can be extremely dangerous because of the ability to devolve into a reinterpret_cast
, and the latter should be preferred when explicit casting is needed, unless you are sure static_cast
will succeed or reinterpret_cast
will fail. Even then, consider the longer, more explicit option.
C-style casts also ignore access control when performing a static_cast
, which means that they have the ability to perform an operation that no other cast can. This is mostly a kludge, though, and in my mind is just another reason to avoid C-style casts.
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Best Answer
From Wikipedia's Virtual function ...
Unlike a non-virtual function, when a virtual function is overridden the most-derived version is used at all levels of the class hierarchy, rather than just the level at which it was created. Therefore if one method of the base class calls a virtual method, the version defined in the derived class will be used instead of the version defined in the base class.
This is in contrast to non-virtual functions, which can still be overridden in a derived class, but the "new" version will only be used by the derived class and below, but will not change the functionality of the base class at all.
whereas..
When a pure virtual method exists, the class is "abstract" and can not be instantiated on its own. Instead, a derived class that implements the pure-virtual method(s) must be used. A pure-virtual isn't defined in the base-class at all, so a derived class must define it, or that derived class is also abstract, and can not be instantiated. Only a class that has no abstract methods can be instantiated.
A virtual provides a way to override the functionality of the base class, and a pure-virtual requires it.