You can use the viewport value instead of ems, pxs, or pts:
1vw = 1% of viewport width
1vh = 1% of viewport height
1vmin = 1vw or 1vh, whichever is smaller
1vmax = 1vw or 1vh, whichever is larger
h1 {
font-size: 5.9vw;
}
h2 {
font-size: 3.0vh;
}
p {
font-size: 2vmin;
}
From CSS-Tricks: Viewport Sized Typography
Original Answer:
If you are ready to opt for CSS3, you can use css3 translate property. Resize based on whatever is bigger. If your height is bigger and width is smaller than container, width will be stretch to 100% and height will be trimmed from both side. Same goes for larger width as well.
Your need, HTML:
<div class="img-wrap">
<img src="http://lorempixel.com/300/160/nature/" />
</div>
<div class="img-wrap">
<img src="http://lorempixel.com/300/200/nature/" />
</div>
<div class="img-wrap">
<img src="http://lorempixel.com/200/300/nature/" />
</div>
And CSS:
.img-wrap {
width: 200px;
height: 150px;
position: relative;
display: inline-block;
overflow: hidden;
margin: 0;
}
div > img {
display: block;
position: absolute;
top: 50%;
left: 50%;
min-height: 100%;
min-width: 100%;
transform: translate(-50%, -50%);
}
Voila! Working: http://jsfiddle.net/shekhardesigner/aYrhG/
Explanation
DIV is set to the relative position. This means all the child elements will get the starting coordinates (origins) from where this DIV starts.
The image is set as a BLOCK element, min-width/height both set to 100% means to resize the image no matter of its size to be the minimum of 100% of it's parent. min is the key. If by min-height, the image height exceeded the parent's height, no problem. It will look for if min-width and try to set the minimum height to be 100% of parents. Both goes vice-versa. This ensures there are no gaps around the div but image is always bit bigger and gets trimmed by overflow:hidden;
Now image, this is set to an absolute position with left:50% and top:50%. Means push the image 50% from the top and left making sure the origin is taken from DIV. Left/Top units are measured from the parent.
Magic moment:
transform: translate(-50%, -50%);
Now, this translate function of CSS3 transform property moves/repositions an element in question. This property deals with the applied element hence the values (x, y) OR (-50%, -50%) means to move the image negative left by 50% of image size and move to the negative top by 50% of image size.
Eg. if Image size was 200px × 150px, transform:translate(-50%, -50%) will calculated to translate(-100px, -75px). % unit helps when we have various size of image.
This is just a tricky way to figure out centroid of the image and the parent DIV and match them.
Apologies for taking too long to explain!
Resources to read more:
Best Answer
Note: This solution changes based on viewport size and not the amount of content
I just found out that this is possible using VW units. They're the units associated with setting the viewport width. There are some drawbacks, such as lack of legacy browser support, but this is definitely something to seriously consider using. Plus you can still provide fallbacks for older browsers like so:
http://css-tricks.com/viewport-sized-typography/ and https://medium.com/design-ux/66bddb327bb1