Css – Removing rounded corners from a element in Chrome/Webkit

cssselectwebkit

The user-agent stylesheet for Chrome gives a border-radius of 5px to all the corners of a <select> element. I've tried getting rid of this by applying a radius of 0px through my external stylesheet, as well inline on the element itself; I've tried both border-radius:0px and -webkit-border-radius:0px; and I've tried the even more specific border-top-left-radius:0px (along with it's -webkit equivalent).

None are working.

When I examine the element in webkit's developer tools, the Computed Style still lists the radius as 5px. But if I click the expander arrow next to it to see the specifics, it reads: element.style – 0px. And below that it shows the external css specification I gave of 0px, along with the user-agent stylesheet specification of 5px. And both of those latter two are crossed out, as they should be.

Any ideas?

Best Answer

This works for me (styles the first appearance not the dropdown list):

select {
  -webkit-appearance: none;
  -webkit-border-radius: 0px;
}

http://jsfiddle.net/fMuPt/

Related Solutions

Html – CSS3’s border-radius property and border-collapse:collapse don’t mix. How to use border-radius to create a collapsed table with rounded corners

I figured it out. You just have to use some special selectors.

The problem with rounding the corners of the table was that the td elements didn't also become rounded. You can solve that by doing something like this:

table tr:last-child td:first-child {
    border-bottom-left-radius: 10px;
}

table tr:last-child td:last-child {
    border-bottom-right-radius: 10px;
}

Now everything rounds properly, except that there's still the issue of border-collapse: collapse breaking everything.

A workaround is to add border-spacing: 0 and leave the default border-collapse: separate on the table.

Sql – How to UPDATE from a SELECT in SQL Server

UPDATE
    Table_A
SET
    Table_A.col1 = Table_B.col1,
    Table_A.col2 = Table_B.col2
FROM
    Some_Table AS Table_A
    INNER JOIN Other_Table AS Table_B
        ON Table_A.id = Table_B.id
WHERE
    Table_A.col3 = 'cool'

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