Django Admin linking to related objects

djangodjango-admin

My app has users who create pages. In the Page screen of the admin, I'd like to list the User who created the page, and in that list, I'd like the username to have a link that goes to the user page in admin (not the Page).

class PageAdmin(admin.ModelAdmin):
    list_display = ('name', 'user', )
    list_display_links = ('name','user',)
admin.site.register(Page, PageAdmin)

I was hoping that by making it a link in the list_display it would default to link to the actual user object, but it still goes to Page.

I'm sure I'm missing something simple here.

Best Answer

Modifying your model isn't necessary, and it's actually a bad practice (adding admin-specific view-logic into your models? Yuck!) It may not even be possible in some scenarios.

Luckily, it can all be achieved from the ModelAdmin class:

from django.urls import reverse
from django.utils.safestring import mark_safe    


class PageAdmin(admin.ModelAdmin):
    # Add it to the list view:
    list_display = ('name', 'user_link', )
    # Add it to the details view:
    readonly_fields = ('user_link',)

    def user_link(self, obj):
        return mark_safe('<a href="{}">{}</a>'.format(
            reverse("admin:auth_user_change", args=(obj.user.pk,)),
            obj.user.email
        ))
    user_link.short_description = 'user'


admin.site.register(Page, PageAdmin)

Edit 2016-01-17: Updated answer to use make_safe, since allow_tags is now deprecated.

Edit 2019-06-14: Updated answer to use django.urls, since as of Django 1.10 django.core.urls has been deprecated.

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You can use the URL resolver directly in a template, there's no need to write your own filter. E.g.

{% url 'admin:index' %}

{% url 'admin:polls_choice_add' %}

{% url 'admin:polls_choice_change' choice.id %}

{% url 'admin:polls_choice_changelist' %}

Ref: Documentation

Python – Multiple ModelAdmins/views for same model in Django admin

I've found one way to achieve what I want, by using proxy models to get around the fact that each model may be registered only once.

class PostAdmin(admin.ModelAdmin):
    list_display = ('title', 'pubdate','user')

class MyPost(Post):
    class Meta:
        proxy = True

class MyPostAdmin(PostAdmin):
    def get_queryset(self, request):
        return self.model.objects.filter(user = request.user)


admin.site.register(Post, PostAdmin)
admin.site.register(MyPost, MyPostAdmin)

Then the default PostAdmin would be accessible at /admin/myapp/post and the list of posts owned by the user would be at /admin/myapp/myposts.

After looking at http://code.djangoproject.com/wiki/DynamicModels, I've come up with the following function utility function to do the same thing:

def create_modeladmin(modeladmin, model, name = None):
    class  Meta:
        proxy = True
        app_label = model._meta.app_label

    attrs = {'__module__': '', 'Meta': Meta}

    newmodel = type(name, (model,), attrs)

    admin.site.register(newmodel, modeladmin)
    return modeladmin

This can be used as follows:

class MyPostAdmin(PostAdmin):
    def get_queryset(self, request):
        return self.model.objects.filter(user = request.user)

create_modeladmin(MyPostAdmin, name='my-posts', model=Post)

Best Answer

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Python – Multiple ModelAdmins/views for same model in Django admin

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