How to get the current URL within a Django template

djangodjango-templates

I was wondering how to get the current URL within a template.

Say my current URL is:

.../user/profile/

How do I return this to the template?

Best Answer

Django 1.9 and above:

## template
{{ request.path }}  #  -without GET parameters 
{{ request.get_full_path }}  # - with GET parameters

Old:

## settings.py
TEMPLATE_CONTEXT_PROCESSORS = (
    'django.core.context_processors.request',
)

## views.py
from django.template import *

def home(request):
    return render_to_response('home.html', {}, context_instance=RequestContext(request))

## template
{{ request.path }}

Related Solutions

Python – How to access the user profile in a Django template

Use {{ request.user.get_profile.whatever }}. Django's templating language automatically calls things that are callable - in this case, the .get_profile() method.

How to combine two or more querysets in a Django view

Concatenating the querysets into a list is the simplest approach. If the database will be hit for all querysets anyway (e.g. because the result needs to be sorted), this won't add further cost.

from itertools import chain
result_list = list(chain(page_list, article_list, post_list))

Using itertools.chain is faster than looping each list and appending elements one by one, since itertools is implemented in C. It also consumes less memory than converting each queryset into a list before concatenating.

Now it's possible to sort the resulting list e.g. by date (as requested in hasen j's comment to another answer). The sorted() function conveniently accepts a generator and returns a list:

result_list = sorted(
    chain(page_list, article_list, post_list),
    key=lambda instance: instance.date_created)

If you're using Python 2.4 or later, you can use attrgetter instead of a lambda. I remember reading about it being faster, but I didn't see a noticeable speed difference for a million item list.

from operator import attrgetter
result_list = sorted(
    chain(page_list, article_list, post_list),
    key=attrgetter('date_created'))

Best Answer

Related Solutions

Python – How to access the user profile in a Django template

How to combine two or more querysets in a Django view

Related Topic