Google-chrome – Chrome, Firefox and Safari not applying XSLT? IE does!

firefoxgoogle-chromesafarixslt

The below is returned to the browser:

    <?xml version="1.0"?>
    <?xml-stylesheet type="text/xsl" href="to_xhtml.xslt"?>
    <root>
      <value>test data</value>
    </root>

Chrome 7 and FF 5 do not appy the XSLT only showing the XML values. IE does apply the XSLT showing the resultant XHTML.

The XSLT file is there and is valid – I can proccess the XML locally and open the resulting XHTML in Chrome and Firefox…

The web server is IIS 6 and interface is PHP 5.3 if that has anything to with it?

UPDATE: XSLT:

<?xml version='1.0'?>
<xsl:stylesheet
  version="1.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns="http://www.w3.org/1999/xhtml">

  <xsl:output 
    method='xml' 
    indent='yes'
    doctype-public='"-//W3C//DTD XHTML Basic 1.1//EN"
    "http://www.w3.org/TR/xhtml-basic/xhtml-basic11.dtd"'/>

  <xsl:template match="/root">
    <html>
      <head>
        <title>
        </title>
      </head>
      <body>
        <p>
            <xsl:value-of select="value"/>
        </p>
    ...
  </html>

Best Answer

You need to ensure your page is served with the correct HTTP Content-Type header value in this case: text/xml, possible in PHP using the header function:

header('Content-type: text/xml');
echo $xmlStr;

*thanks to meder who lead me in the right direction for this.

Also In Chrome and Safari an error still occurs while applying the XSLT because of the above doctype-public value:

<xsl:output 
method='xml' 
indent='yes'
doctype-public='"-//W3C//DTD XHTML Basic 1.1//EN"
"http://www.w3.org/TR/xhtml-basic/xhtml-basic11.dtd"'/>;

It should be:

<xsl:output 
  method="xml"
  indent="yes"
  doctype-public="-//W3C//DTD XHTML Basic 1.1//EN"
  doctype-system="http://www.w3.org/TR/xhtml-basic/xhtml-basic11.dtd"/>

The doctype-public attribute should not even be looked at if doctype-system is not specfied according to the spec.

*thanks to LarsH for pointing out doctype-system should be in a separate value.

Related Solutions

Visual-studio – XSLT Intellisense in Visual Studio 2008

The Xml editor does support the standard xsl intellisense but it will strictly apply the schema. Hence you first need to enter a <xsl:stylesheet> and start adding children to it before you will see any xsl options. This is because all other other xsl elements need be children of either the xsl:stylesheet element or some other xsl element.

XML to CSV using XSLT help

This simple transformation produces the wanted result:

<xsl:stylesheet version="1.0"
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output method="text"/>
 <xsl:strip-space elements="*"/>

    <xsl:template match="/">
    <xsl:apply-templates select="//text()"/>
    </xsl:template>

    <xsl:template match="text()">
      <xsl:copy-of select="."/>
      <xsl:if test="not(position()=last())">,</xsl:if>
    </xsl:template>
</xsl:stylesheet>

Do note the use of:

 <xsl:strip-space elements="*"/>

to discard any white-space-only text nodes.

Update: AJ raised the problem that the results shoud be grouped in recirds/tuples per line. It isn't defined in the question what a record/tuple should exactly be. Therefore the current solution solves the two problems of white-space-only text nodes and of missing commas, but does not aim to grop the output into records/tuples.

Best Answer

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Visual-studio – XSLT Intellisense in Visual Studio 2008

XML to CSV using XSLT help

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