Groovy custom sort a map by value

groovymapsorting

I have a map such as

m=[
     "james":"silly boy",
     "janny":"Crazy girl",
     "jimmy":"funny man",
     "georges":"massive fella"
];

I want to sort this map by its value but ignoring the case (this is really why the custom sort is needed). Hence I figured I had to implement a custom sort using a closure. But I'm brand new at Groovy and been struggling to get this very simple task done!

The desired results would be:

["janny":"Crazy girl", "jimmy":"funny man", "georges":"massive fella", "james":"silly boy"]

Thanks !

Best Answer

To sort with case insensitive, use

m.sort { it.value.toLowerCase() }

Related Solutions

C# – How to sort a dictionary by value

Use LINQ:

Dictionary<string, int> myDict = new Dictionary<string, int>();
myDict.Add("one", 1);
myDict.Add("four", 4);
myDict.Add("two", 2);
myDict.Add("three", 3);

var sortedDict = from entry in myDict orderby entry.Value ascending select entry;

This would also allow for great flexibility in that you can select the top 10, 20 10%, etc. Or if you are using your word frequency index for type-ahead, you could also include StartsWith clause as well.

Python – How to sort a list of dictionaries by a value of the dictionary

The sorted() function takes a key= parameter

newlist = sorted(list_to_be_sorted, key=lambda d: d['name'])

Alternatively, you can use operator.itemgetter instead of defining the function yourself

from operator import itemgetter
newlist = sorted(list_to_be_sorted, key=itemgetter('name'))

For completeness, add reverse=True to sort in descending order

newlist = sorted(list_to_be_sorted, key=itemgetter('name'), reverse=True)

Best Answer

Related Solutions

C# – How to sort a dictionary by value

Python – How to sort a list of dictionaries by a value of the dictionary

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