How to get in a Visualforce page controller a value from a custom component controller

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I'm trying do develop a visualforce custom component which is an entity chooser. This custom component displays a UI which helps browsing some records. It's possible to select one record, and I'd like to get it from outside the component or its controller.

I've looked at the standard salesforce binding with assignTo bug it's not bidirectional…

Hope someone can help me..
Thanks

Best Answer

Are you passing an object into the component? Objects are passed by reference, so if your component has an attribute that takes an object and does something to it, your outer page controller will be able to access the changed values.

If you were to pass in a shell object, ie. if your UI is allowing a user to select an Account.

Class SelectedAccount
{
  public Account theAccount {get;set;}
}

Component:

<apex:component controller="ComponentController">
   <apex:attribute type="SelectedAccount" name="userSelectedAccount" description="Selected Account" assignTo="{!selectedAccount}"
</apex:component>

Component Controller:

public class ComponentController
{
  public selectedAccount;

  public void ComponentController(){}

  public PageReference selectAccountFromUI(Account selected)
  {
    selectedAccount.theAccount = selected;

    return null;
  }
}

Page Using the Component:

<c:MyAccountComponent userSelectedAccount="{!instanceOfSelectedAccount}"/>

This would allow you to assign the user selected account into the instance of wrapper object which is owned by the outer controller. You can then reference:

instanceOfSelectedAccount.theAccount

from your main Visualforce Pages controller.

Related Solutions

Visualforce Custom Controller List

You could use an outputLink:

<apex:pageBlockTable value="{!CasePagination}" var="c">
    <apex:column value="{!c.Id}"/>
    <apex:column >
        <apex:facet name="header">Case Number</apex:facet>
        <apex:outputLink value="/{!c.Id}">{!c.CaseNumber}</apex:outputLink>
    </apex:column>
    <apex:column value="{!c.Subject}" onclick="openCase"/>
    <apex:column value="{!c.Status}" onclick="openCase"/>
</apex:pageBlockTable>

Custom Button or Link to a Visualforce page with a custom controller

Best to do this from an Apex PageReference return value. Something like this will work:

public PageReference returnPage()
{
   return Page.MyExamplePage;
}

Then call this from Visualforce:

<apex:commandButton value="Go To New Page" action="{!returnPage}"/>

The Apex Page call will handle the translation for you.

[EDIT]

Create a bare bones Visualforce page like this:

<apex:page standardController="Opportunity" extensions="TheController" action="{!returnPage}"/>

Add the above returnPage() method to a new TheController (or whatever) class. It doesn't even need a constructor. The class can look like this:

public TheController
{
   public PageReference returnPage()
   {
      return Page.MyExamplePage;
   }
}

Then from the Opportunity settings page go to Buttons and Links and create a new custom Visualforce button selecting the new page you just created.

That should do it.

Best Answer

Related Solutions

Visualforce Custom Controller List

Custom Button or Link to a Visualforce page with a custom controller

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