How to select these elements with Xpath

xpathxslt

I have a document, something like this: 

<root>
   <A node="1"/>
   <B node="2"/>
   <A node="3"/>
   <A node="4"/>
   <B node="5"/>
   <B node="6"/>
   <A node="7"/>
   <A node="8"/>
   <B node="9"/>
</root>

Using xpath, How can I select all B elements that consecutively follow a given A element?

It's something like following-silbing::B, except I want them to be only the immediately following elements.

If I am on A (node==1), then I want to select node 2.
If I am on A (node==3), then I want to select nothing.
If I am on A (node==4), then I want to select 5 and 6.

Can I do this in xpath? EDIT: It is within an XSL stylesheet select statement.

EDIT2: I don't want to use the node attribute on the various elements as a unique identifier. I included the node attribute only for purposes of illustrating my point. In the actual XML doc, I don't have an attribute that I use as a unique identifer. The xpath "following-sibling::UL[preceding-sibling::LI[1]/@node = current()/@node]"
keys on the node attribute, and that's not what I want.

Best Answer

Short answer (assuming current() is ok, since this is tagged xslt):

following-sibling::B[preceding-sibling::A[1]/@node = current()/@node]

Example stylesheet:

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
    <xsl:output method="xml"/>
    <xsl:template match="/">
        <xsl:apply-templates select="/root/A"/>
    </xsl:template>

    <xsl:template match="A">
        <div>A: <xsl:value-of select="@node"/></div>
        <xsl:apply-templates select="following-sibling::B[preceding-sibling::A[1]/@node = current()/@node]"/>
    </xsl:template>

    <xsl:template match="B">
        <div>B: <xsl:value-of select="@node"/></div>
    </xsl:template>
</xsl:stylesheet>

Good luck!

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