How to write a DOS script to extract all the file name in a directory

I think there's a /v option for findstr which is equivalent to grep -v (include all lines that don't contain the text. So I'd be looking at:

dir | findstr /vi ".pdf"

The syntax may be slightly different, I haven't had much need to use it and I don'r run Windows at my current location.

Use findstr /? from a command prompt for details.

Or, if you install CygWin (my tool of choice for this sort of stuff), you can just use grep itself:

ls -al | grep -vi '\.pdf$'

Addendum:

I actually didn't realize this but apparently findstr also support regexes so you can use:

dir | findstr /vi "\.pdf$"

just the same as grep (I haven't tested this, I only just found it on TechNet, so you'll need to test it yourself).

php/win32 ships with the COM/.net extension built-in. You can use it to create a WSH FileSystemObject and then query the ShortPath property of the File object.

<?php
$objFSO = new COM("Scripting.FileSystemObject");
$objFile = $objFSO->GetFile(FILE);
echo "path: ", $objFile->Path, "\nshort path: ", $objFile->ShortPath;

path: C:\Dokumente und Einstellungen\Volker\Desktop\test.php
short path: C:\DOKUME~1\Volker\Desktop\test.php