There are several differences between HashMap and Hashtable in Java:
Hashtable is synchronized, whereas HashMap is not. This makes HashMap better for non-threaded applications, as unsynchronized Objects typically perform better than synchronized ones.
Hashtable does not allow null keys or values. HashMap allows one null key and any number of null values.
One of HashMap's subclasses is LinkedHashMap, so in the event that you'd want predictable iteration order (which is insertion order by default), you could easily swap out the HashMap for a LinkedHashMap. This wouldn't be as easy if you were using Hashtable.
Since synchronization is not an issue for you, I'd recommend HashMap. If synchronization becomes an issue, you may also look at ConcurrentHashMap.
From the Java Tutorial:
Nested classes are divided into two categories: static and non-static. Nested classes that are declared static are simply called static nested classes. Non-static nested classes are called inner classes.
Static nested classes are accessed using the enclosing class name:
OuterClass.StaticNestedClass
For example, to create an object for the static nested class, use this syntax:
OuterClass.StaticNestedClass nestedObject = new OuterClass.StaticNestedClass();
Objects that are instances of an inner class exist within an instance of the outer class. Consider the following classes:
class OuterClass {
...
class InnerClass {
...
}
}
An instance of InnerClass can exist only within an instance of OuterClass and has direct access to the methods and fields of its enclosing instance.
To instantiate an inner class, you must first instantiate the outer class. Then, create the inner object within the outer object with this syntax:
OuterClass outerObject = new OuterClass()
OuterClass.InnerClass innerObject = outerObject.new InnerClass();
see: Java Tutorial - Nested Classes
For completeness note that there is also such a thing as an inner class without an enclosing instance:
class A {
int t() { return 1; }
static A a = new A() { int t() { return 2; } };
}
Here, new A() { ... } is an inner class defined in a static context and does not have an enclosing instance.
Best Answer
In your example, there is no difference in behavioural semantics. In Java, all instance field initializers (and instance blocks) are executed after superclass initialization, and before the body of the constructor; see JLS 12.5.
The difference lies in code readability and (in other examples) avoiding repetitious coding and fragility1. These need to be assessed on a case-by-case basis.
It is also worth noting that there are some cases where you have to initialize in the constructor; i.e. when the initialization depends on a constructor parameter.
1 - The repetitiousness and fragility issues are flip-sides of the same thing. If you have multiple constructors, the "initialize in constructor" approach tends to lead to repetition. And if you add extra fields, you might to add the initialization to all relevant constructors; i.e. fragility.