Java – How to tell Java SAX Parser to ignore invalid character references

error handlingjavasaxxml

When trying to parse incorrect XML with a character reference such as &#x1, Java's SAX Parser dies a horrible death with a fatal error such as

    org.xml.sax.SAXParseException: Character reference "&#x1"
                                   is an invalid XML character.

Is there any way around this? Will I have to clean up the XML file before I hand it off to the SAX Parser? If so, is there an elegant way of going about this?

Best Answer

Use XML 1.1! skaffman is completely right, but you can just stick <?xml version="1.1"?> on the top of your files and you'll be in good shape. If you're dealing with streams, write a wrapper that rewrites or adds that processing instruction.

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Java – How to efficiently iterate over each entry in a Java Map

Map<String, String> map = ...
for (Map.Entry<String, String> entry : map.entrySet()) {
    System.out.println(entry.getKey() + "/" + entry.getValue());
}

On Java 10+:

for (var entry : map.entrySet()) {
    System.out.println(entry.getKey() + "/" + entry.getValue());
}

Java – How to call one constructor from another in Java

Yes, it is possible:

public class Foo {
    private int x;

    public Foo() {
        this(1);
    }

    public Foo(int x) {
        this.x = x;
    }
}

To chain to a particular superclass constructor instead of one in the same class, use super instead of this. Note that you can only chain to one constructor, and it has to be the first statement in your constructor body.

See also this related question, which is about C# but where the same principles apply.

Best Answer

Related Solutions

Java – How to efficiently iterate over each entry in a Java Map

Java – How to call one constructor from another in Java

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