Java – passing array in oracle stored procedure

arraysjavaoraclestored-procedures

I have a Java app accessing an oracle stored procedure. The arguments to the stored procedure include an array type. I do it like the following…

con = this._getConnection();  
Connection narrowdConn = (Connection)WSJdbcUtil.getNativeConnection( (WSJdbcConnection)con );  

callable = con.prepareCall("{call MY_PKG.MY_PROCEDURE(?, ?)}");  


ArrayDescriptor arrayDescriptor = ArrayDescriptor.createDescriptor("VARCHAR2_ARR", narrowdConn);  
ARRAY arrayArg1 = new ARRAY(arrayDescriptor, con, docNames);  
ARRAY arrayArg2 = new ARRAY(arrayDescriptor, con, docTypes);  

callable.setArray(1, arrayArg1);  
callable.setArray(2, arrayArg2);  

callable.execute();

Now, I am getting this Exception…

java.sql.SQLException: invalid name pattern: MY_PKG.VARCHAR2_ARR

VARCHAR2_ARR is a public TYPE, defined inside an Oracle Package like the following:

TYPE VARCHAR2_ARR IS TABLE OF VARCHAR2(50);

And used as such in my stored proc…

PROCEDURE MY_PROCEDURE  
    (V_ARR_ARG1  IN VARCHAR2_ARR,  
     V_ARR_ARG2  IN VARCHAR2_ARR)

Best Answer

the type VARCHAR2_ARR is a PLSQL type, you won't be able to interface it directly from java. I suggest you look into this thread on AskTom regarding a similar question.

Here are a couple suggestions:

create a SQL TYPE that you can bind from java
insert into a temporary table from java and read from it in plsql

In both cases you will have to either modify the PLSQL procedure or add a new translation procedure.

Related Solutions

Java – Is Java “pass-by-reference” or “pass-by-value”

Java is always pass-by-value. Unfortunately, when we deal with objects we are really dealing with object-handles called references which are passed-by-value as well. This terminology and semantics easily confuse many beginners.

It goes like this:

public static void main(String[] args) {
    Dog aDog = new Dog("Max");
    Dog oldDog = aDog;

    // we pass the object to foo
    foo(aDog);
    // aDog variable is still pointing to the "Max" dog when foo(...) returns
    aDog.getName().equals("Max"); // true
    aDog.getName().equals("Fifi"); // false
    aDog == oldDog; // true
}

public static void foo(Dog d) {
    d.getName().equals("Max"); // true
    // change d inside of foo() to point to a new Dog instance "Fifi"
    d = new Dog("Fifi");
    d.getName().equals("Fifi"); // true
}

In the example above aDog.getName() will still return "Max". The value aDog within main is not changed in the function foo with the Dog "Fifi" as the object reference is passed by value. If it were passed by reference, then the aDog.getName() in main would return "Fifi" after the call to foo.

Likewise:

public static void main(String[] args) {
    Dog aDog = new Dog("Max");
    Dog oldDog = aDog;

    foo(aDog);
    // when foo(...) returns, the name of the dog has been changed to "Fifi"
    aDog.getName().equals("Fifi"); // true
    // but it is still the same dog:
    aDog == oldDog; // true
}

public static void foo(Dog d) {
    d.getName().equals("Max"); // true
    // this changes the name of d to be "Fifi"
    d.setName("Fifi");
}

In the above example, Fifi is the dog's name after call to foo(aDog) because the object's name was set inside of foo(...). Any operations that foo performs on d are such that, for all practical purposes, they are performed on aDog, but it is not possible to change the value of the variable aDog itself.

For more information on pass by reference and pass by value, consult the following SO answer: https://stackoverflow.com/a/430958/6005228. This explains more thoroughly the semantics and history behind the two and also explains why Java and many other modern languages appear to do both in certain cases.

Java – Create ArrayList from array

new ArrayList<>(Arrays.asList(array));

Best Answer

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Java – Is Java “pass-by-reference” or “pass-by-value”

Java – Create ArrayList from array

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