Java – the best way to find the users home directory in Java

cross platformhome-directoryjava

The difficulty is that it should be cross platform. Windows 2000, XP, Vista, OSX, Linux, other unix variants. I am looking for a snippet of code that can accomplish this for all platforms, and a way to detect the platform.

Now, you should be aware of bug 4787931 that user.home does not work correctly, so please do not provide me of textbook answers, I can find these myself in the manuals.

Best Answer

The bug you reference (bug 4787391) has been fixed in Java 8. Even if you are using an older version of Java, the System.getProperty("user.home") approach is probably still the best. The user.home approach seems to work in a very large number of cases. A 100% bulletproof solution on Windows is hard, because Windows has a shifting concept of what the home directory means.

If user.home isn't good enough for you I would suggest choosing a definition of home directory for windows and using it, getting the appropriate environment variable with System.getenv(String).

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Java – What are the differences between a HashMap and a Hashtable in Java

There are several differences between HashMap and Hashtable in Java:

Hashtable is synchronized, whereas HashMap is not. This makes HashMap better for non-threaded applications, as unsynchronized Objects typically perform better than synchronized ones.
Hashtable does not allow null keys or values. HashMap allows one null key and any number of null values.
One of HashMap's subclasses is LinkedHashMap, so in the event that you'd want predictable iteration order (which is insertion order by default), you could easily swap out the HashMap for a LinkedHashMap. This wouldn't be as easy if you were using Hashtable.

Since synchronization is not an issue for you, I'd recommend HashMap. If synchronization becomes an issue, you may also look at ConcurrentHashMap.

Java – How does the Java ‘for each’ loop work

for (Iterator<String> i = someIterable.iterator(); i.hasNext();) {
    String item = i.next();
    System.out.println(item);
}

Note that if you need to use i.remove(); in your loop, or access the actual iterator in some way, you cannot use the for ( : ) idiom, since the actual iterator is merely inferred.

As was noted by Denis Bueno, this code works for any object that implements the Iterable interface.

Also, if the right-hand side of the for (:) idiom is an array rather than an Iterable object, the internal code uses an int index counter and checks against array.length instead. See the Java Language Specification.

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