Javascript – disable jquery-chosen dropdown

javascriptjqueryjquery-chosen

I have a select div that I'm using the chosen jquery plugin to style and add features to (most notably, search). The div looks something like this,

 <select data-placeholder="add a foobar" id="foobar" style="width: 350px;">
 <option value=""></option>
 </select>

And I'm using the chosen plugin like this,

 $('#foobar').chosen();

While some AJAX is loading, I'd like to disable the entire <select> div. Maybe with something like this,

 $('#foobar').disable()

or this

 $('#foobar').prop('disabled', true)

I think you get the idea.

Any ideas on how to do this? I've tried a number of different things, like using jquery idioms for disabling things, disabling the <select> which just disables the underlying select, not the chosen stuff on top of it. I've even resorted to manually adding another div with a high z-index to just grey out the box, but I think that this is likely to be ugly and buggy.

Thanks for the help!

Best Answer

You are disabling just your select, but chosen renders it as divs, and spans, etc. So after disabling your select you need to update the plugin to make the select widget disabled too. You can try this way:

$('#foobar').prop('disabled', true).trigger("liszt:updated");

//For non-older versions of chosen you would want to do:

$('#foobar').prop('disabled', true).trigger("chosen:updated");

I found the information here

Fiddle

Once you update the widget all it does is it unbinds the click or other events on the plugin and changes its opacity to 0.5. As there is no real disabled state for a div.

Related Solutions

Javascript – n “exists” function for jQuery

In JavaScript, everything is 'truthy' or 'falsy', and for numbers 0 means false, everything else true. So you could write:

if ($(selector).length)

You don't need that >0 part.

Javascript – Add table row in jQuery

The approach you suggest is not guaranteed to give you the result you're looking for - what if you had a tbody for example:

<table id="myTable">
  <tbody>
    <tr>...</tr>
    <tr>...</tr>
  </tbody>
</table>

You would end up with the following:

<table id="myTable">
  <tbody>
    <tr>...</tr>
    <tr>...</tr>
  </tbody>
  <tr>...</tr>
</table>

I would therefore recommend this approach instead:

$('#myTable tr:last').after('<tr>...</tr><tr>...</tr>');

You can include anything within the after() method as long as it's valid HTML, including multiple rows as per the example above.

Update: Revisiting this answer following recent activity with this question. eyelidlessness makes a good comment that there will always be a tbody in the DOM; this is true, but only if there is at least one row. If you have no rows, there will be no tbody unless you have specified one yourself.

DaRKoN_ suggests appending to the tbody rather than adding content after the last tr. This gets around the issue of having no rows, but still isn't bulletproof as you could theoretically have multiple tbody elements and the row would get added to each of them.

Weighing everything up, I'm not sure there is a single one-line solution that accounts for every single possible scenario. You will need to make sure the jQuery code tallies with your markup.

I think the safest solution is probably to ensure your table always includes at least one tbody in your markup, even if it has no rows. On this basis, you can use the following which will work however many rows you have (and also account for multiple tbody elements):

$('#myTable > tbody:last-child').append('<tr>...</tr><tr>...</tr>');

Best Answer

Fiddle

Related Solutions

Javascript – n “exists” function for jQuery

Javascript – Add table row in jQuery

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