Jquery – how to resolve Error: $ is not defined in jquery

asp.netasp.net-mvcjquery

i am using asp.net mvc in that i am using partial views but i get the following error

Error: $ is not defined
Line: 159

it is for the java script its not getting reference. i included the java script in site.master

     <script src="../../Scripts/jquery-1.2.6.js" type="text/javascript"></script>
     <script src="../../Scripts/jquery-1.3.2.js" type="text/javascript"></script>
     <script src="../../Scripts/ui.core.js" type="text/javascript"></script>
     <script src="../../Scripts/ui.datepicker.js" type="text/javascript"></script>

first js is for partial view. and my function is:

<script type="text/javascript">
    $(document).ready(function() {
        var dt = { changeYear: true, yearRange: "-6:+6" }
        $("#FromDate").datepicker(dt);
    });
</script>

so can you tell me how to resolve reference problem.because of that date picker is also not working and partial views also not working but on local host it works fine but on server nothing is working.
i also used src="<%= Url.Content("~/Scripts/XXXX.js")%>" but still its not working on server.
thank you.

Best Answer

The problem will be with the path to the scripts I think. Where you have

src="../../Scripts/jquery-1.2.6.js"

you probably need to change this to something like

src="/Something/Scripts/jquery-1.2.6.js"

you could also try referencing an external version (as SO does).

<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>

Related Solutions

Javascript – n “exists” function for jQuery

In JavaScript, everything is 'truthy' or 'falsy', and for numbers 0 means false, everything else true. So you could write:

if ($(selector).length)

You don't need that >0 part.

Javascript – Add table row in jQuery

The approach you suggest is not guaranteed to give you the result you're looking for - what if you had a tbody for example:

<table id="myTable">
  <tbody>
    <tr>...</tr>
    <tr>...</tr>
  </tbody>
</table>

You would end up with the following:

<table id="myTable">
  <tbody>
    <tr>...</tr>
    <tr>...</tr>
  </tbody>
  <tr>...</tr>
</table>

I would therefore recommend this approach instead:

$('#myTable tr:last').after('<tr>...</tr><tr>...</tr>');

You can include anything within the after() method as long as it's valid HTML, including multiple rows as per the example above.

Update: Revisiting this answer following recent activity with this question. eyelidlessness makes a good comment that there will always be a tbody in the DOM; this is true, but only if there is at least one row. If you have no rows, there will be no tbody unless you have specified one yourself.

DaRKoN_ suggests appending to the tbody rather than adding content after the last tr. This gets around the issue of having no rows, but still isn't bulletproof as you could theoretically have multiple tbody elements and the row would get added to each of them.

Weighing everything up, I'm not sure there is a single one-line solution that accounts for every single possible scenario. You will need to make sure the jQuery code tallies with your markup.

I think the safest solution is probably to ensure your table always includes at least one tbody in your markup, even if it has no rows. On this basis, you can use the following which will work however many rows you have (and also account for multiple tbody elements):

$('#myTable > tbody:last-child').append('<tr>...</tr><tr>...</tr>');

Best Answer

Related Solutions

Javascript – n “exists” function for jQuery

Javascript – Add table row in jQuery

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