JQuery .load() wait till content is loaded

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How to prevent jQuery $('body').load('something.php'); from changing any DOM till all the content from something.php (including images,js) is fully loaded

-Lets say some actual content is:

Hello world

And something.php content is:

image that loads for 10 seconds
20 js plugins

After firing .load() function nothing should happen, till images an js files are fully loaded, and THEN instantly change the content.

some preloader may appear, but its not subject of question.

[edit]———————————————————————-

My solution for that was css code (css is loaded always before dom is build) that has cross-browser opacity 0.

.transparent{
    -moz-opacity: 0.00;
    opacity: 0.00;
    -ms-filter:"progid:DXImageTransform.Microsoft.Alpha"(Opacity=0);
    filter: progid:DXImageTransform.Microsoft.Alpha(opacity=0);
    filter:alpha(opacity=0);
}

And it prevent from bad flickr of content usually but not always. Now its possible to detect somehow that content is loaded by jQuery ajax and apply some show timeout and so on. But in fact question is still open.

To make now a little more simple example for that question:

How to begin changing DOM after $('body').load('something.php') with 3000ms delay after clicking the link that fire .load('something.php') function? (Browser should start downloading instantly, but DOM changing has to be initiated later)

Best Answer

Use .get instead and assign the contents in the success callback:

$.get('something.php', function(result) {
    $('body').html(result);
});

Related Solutions

Javascript – n “exists” function for jQuery

In JavaScript, everything is 'truthy' or 'falsy', and for numbers 0 means false, everything else true. So you could write:

if ($(selector).length)

You don't need that >0 part.

Javascript – Add table row in jQuery

The approach you suggest is not guaranteed to give you the result you're looking for - what if you had a tbody for example:

<table id="myTable">
  <tbody>
    <tr>...</tr>
    <tr>...</tr>
  </tbody>
</table>

You would end up with the following:

<table id="myTable">
  <tbody>
    <tr>...</tr>
    <tr>...</tr>
  </tbody>
  <tr>...</tr>
</table>

I would therefore recommend this approach instead:

$('#myTable tr:last').after('<tr>...</tr><tr>...</tr>');

You can include anything within the after() method as long as it's valid HTML, including multiple rows as per the example above.

Update: Revisiting this answer following recent activity with this question. eyelidlessness makes a good comment that there will always be a tbody in the DOM; this is true, but only if there is at least one row. If you have no rows, there will be no tbody unless you have specified one yourself.

DaRKoN_ suggests appending to the tbody rather than adding content after the last tr. This gets around the issue of having no rows, but still isn't bulletproof as you could theoretically have multiple tbody elements and the row would get added to each of them.

Weighing everything up, I'm not sure there is a single one-line solution that accounts for every single possible scenario. You will need to make sure the jQuery code tallies with your markup.

I think the safest solution is probably to ensure your table always includes at least one tbody in your markup, even if it has no rows. On this basis, you can use the following which will work however many rows you have (and also account for multiple tbody elements):

$('#myTable > tbody:last-child').append('<tr>...</tr><tr>...</tr>');

Best Answer

Related Solutions

Javascript – n “exists” function for jQuery

Javascript – Add table row in jQuery

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