Php – Does pg_prepare() prepared statement (not PDO) prevent SQL-Injection

PHPpostgresqlprepared-statementSecurity

PDO ist not supported in target system I'm working on and though I seek a solution for preventing SQL-Injection using PHP 5.1.x on a PostGres-DB 8.2+. There is at the moment no chance of switching to PDO.

My solution at the moment is pg_prepare-prepared statement:

// Trying to prevent SQL-Injection
$query = 'SELECT * FROM user WHERE login=$1 and password=md5($2)';
$result = pg_prepare($dbconn, "", $query);
$result = pg_execute($dbconn, "", array($_POST["user"], $_POST["password"]));
if (pg_num_rows($result) < 1) {
  die ("failure");
}

But pg_prepare-documentation lacks about an important information:

it tells about "later usage"

pg_prepare() creates a prepared statement for later execution with
pg_execute() or pg_send_execute().[…]

it tells about "named/anonymous statements"

The function creates a prepared statement named stmtname from the
query string, which must contain a single SQL command. stmtname may be
"" to create an unnamed statement, in which case any pre-existing
unnamed statement is automatically replaced;[…]

it tells about "typecasting"

Prepared statements for use with pg_prepare() can also be created by
executing SQL PREPARE statements. (But pg_prepare() is more flexible
since it does not require parameter types to be pre-specified.) Also,
although there is no PHP function for deleting a prepared statement,
the SQL DEALLOCATE statement can be used for that purpose.

but it does not tell, if this implementation of prepared statements is safe from SQL-injection

*Nearly all comments by this security question refers to the PDO-solution, where in documentation is noticed that the driver prevents SQL-injection. But if an easy solution may be pg_prepare, I would use pg_prepare at the moment.*

Thanks for this important information of maybe a best practice solution.

EDIT (after marked as solution):
Thanks for very enlightening answers!

  • I marked the solution of Frank Heikens as best answer, cause it explains an important point in SQL-injection. A programmer may use prepared statemtents, but the SQL-injection-lack may still be there by mistake!
  • Aside from Frank Heikens answer, hoppa shows that the SQL-injection is prevented using pg_prepare/pg_query_params. Thanks though.
  • Will now use an optimized code with pg_query_params (thanks to Milen A. Radev)
  • And pg_escape_string() as alternative when it comes to it (thanks to halfer)

All answers are helpfully 🙂

// Trying to prevent SQL-Injection (**updated**)
$sql_query = 'SELECT * FROM user WHERE login=$1 and password=md5($2);';
$result = pg_query_params($dbconn_login, $sql_query, array($_POST["user"], $_POST["password"]));
if (pg_num_rows($result) < 1) {
  die('failure');
}

Best Answer

A prepared statement is safe from SQL injection because nobody can change the queryplan after it's prepared. But, if your statement is already compromised, you still suffer from SQL injection:

<?php 
// how NOT to construct your SQL....
$query = 'SELECT * FROM user WHERE login=$1 and password=md5($2) LIMIT '. $_POST['limit']; -- injection!
$result = pg_prepare($dbconn, "", $query);
$result = pg_execute($dbconn, "", array($_POST["user"], $_POST["password"]));
if (pg_num_rows($result) < 1) {
  die ("failure");
}
?>