Update: June-2021
For a specific case when you need all query params:
const urlSearchParams = new URLSearchParams(window.location.search);
const params = Object.fromEntries(urlSearchParams.entries());
Update: Sep-2018
You can use URLSearchParams which is simple and has decent (but not complete) browser support.
const urlParams = new URLSearchParams(window.location.search);
const myParam = urlParams.get('myParam');
Original
You don't need jQuery for that purpose. You can use just some pure JavaScript:
function getParameterByName(name, url = window.location.href) {
name = name.replace(/[\[\]]/g, '\\$&');
var regex = new RegExp('[?&]' + name + '(=([^&#]*)|&|#|$)'),
results = regex.exec(url);
if (!results) return null;
if (!results[2]) return '';
return decodeURIComponent(results[2].replace(/\+/g, ' '));
}
Usage:
// query string: ?foo=lorem&bar=&baz
var foo = getParameterByName('foo'); // "lorem"
var bar = getParameterByName('bar'); // "" (present with empty value)
var baz = getParameterByName('baz'); // "" (present with no value)
var qux = getParameterByName('qux'); // null (absent)
NOTE: If a parameter is present several times (?foo=lorem&foo=ipsum
), you will get the first value (lorem
). There is no standard about this and usages vary, see for example this question: Authoritative position of duplicate HTTP GET query keys.
NOTE: The function is case-sensitive. If you prefer case-insensitive parameter name, add 'i' modifier to RegExp
NOTE: If you're getting a no-useless-escape eslint error, you can replace name = name.replace(/[\[\]]/g, '\\$&');
with name = name.replace(/[[\]]/g, '\\$&')
.
This is an update based on the new URLSearchParams specs to achieve the same result more succinctly. See answer titled "URLSearchParams" below.
This always works for me:
ini_set('display_errors', '1');
ini_set('display_startup_errors', '1');
error_reporting(E_ALL);
However, this doesn't make PHP to show parse errors - the only way to show those errors is to modify your php.ini with this line:
display_errors = on
(if you don't have access to php.ini
, then putting this line in .htaccess
might work too):
php_flag display_errors 1
Best Answer
You can use
strtok
to get string before first occurence of?
strtok()
represents the most concise technique to directly extract the substring before the?
in the querystring.explode()
is less direct because it must produce a potentially two-element array by which the first element must be accessed.Some other techniques may break when the querystring is missing or potentially mutate other/unintended substrings in the url -- these techniques should be avoided.
A demonstration:
Output: