Php – Why does the following PHP code fail

You can use either date or strftime. In this case I'd say it doesn't matter as a year is a year, no matter what (unless there's a locale that formats the year differently?)

For example:

<?php echo date("Y"); ?>

On a side note, when formatting dates in PHP it matters when you want to format your date in a different locale than your default. If so, you have to use setlocale and strftime. According to the php manual on date:

To format dates in other languages, you should use the setlocale() and strftime() functions instead of date().

From this point of view, I think it would be best to use strftime as much as possible, if you even have a remote possibility of having to localize your application. If that's not an issue, pick the one you like best.

The time would go by your server time. An easy workaround for this is to manually set the timezone by using date_default_timezone_set before the date() or time() functions are called to.

I'm in Melbourne, Australia so I have something like this:

date_default_timezone_set('Australia/Melbourne');

Or another example is LA - US:

date_default_timezone_set('America/Los_Angeles');

You can also see what timezone the server is currently in via:

date_default_timezone_get();

So something like:

$timezone = date_default_timezone_get();
echo "The current server timezone is: " . $timezone;

So the short answer for your question would be:

// Change the line below to your timezone!
date_default_timezone_set('Australia/Melbourne');
$date = date('m/d/Y h:i:s a', time());

Then all the times would be to the timezone you just set :)