Either var_export
or set print_r
to return the output instead of printing it.
Example from PHP manual
$b = array (
'm' => 'monkey',
'foo' => 'bar',
'x' => array ('x', 'y', 'z'));
$results = print_r($b, true); // $results now contains output from print_r
You can then save $results
with file_put_contents
. Or return it directly when writing to file:
file_put_contents('filename.txt', print_r($b, true));
JLS # 8.4.2. Method Signature
The signature of a method m1 is a subsignature of the signature of a method m2 if either:
m2 has the same signature as m1, or
the signature of m1 is the same as the erasure (ยง4.6) of the
signature of m2.
As per above rule as your parent do not have an erasure and your child has one so it is not a valid overriding.
JLS#8.4.8.3. Requirements in Overriding and Hiding
Example 8.4.8.3-4. Erasure Affects Overriding
A class cannot have two member methods with the same name and type erasure:
class C<T> {
T id (T x) {...}
}
class D extends C<String> {
Object id(Object x) {...}
}
This is illegal since D.id(Object) is a member of D, C.id(String) is declared in a supertype of D, and:
- The two methods have the same name, id
- C.id(String) is accessible to D
- The signature of D.id(Object) is not a subsignature of that of
C.id(String)
- The two methods have the same erasure
Two different methods of a class may not override methods with the same erasure:
class C<T> {
T id(T x) {...}
}
interface I<T> {
T id(T x);
}
class D extends C<String> implements I<Integer> {
public String id(String x) {...}
public Integer id(Integer x) {...}
}
This is also illegal, since D.id(String) is a member of D, D.id(Integer) is declared in D, and:
- The two methods have the same name, id
- D.id(Integer) is accessible to D
- The two methods have different signatures (and neither is a
subsignature of the other)
- D.id(String) overrides C.id(String) and D.id(Integer)
overrides I.id(Integer) yet the two overridden methods have the same
erasure
Also It gives example of a case where it is allowed from super to child
The notion of subsignature is designed to express a relationship between two methods whose signatures are not identical, but in which one may override the other. Specifically, it allows a method whose signature does not use generic types to override any generified version of that method. This is important so that library designers may freely generify methods independently of clients that define subclasses or subinterfaces of the library.
Consider the example:
class CollectionConverter {
List toList(Collection c) {...}
}
class Overrider extends CollectionConverter {
List toList(Collection c) {...}
}
Now, assume this code was written before the introduction of generics, and now the author of class CollectionConverter decides to generify the code, thus:
class CollectionConverter {
<T> List<T> toList(Collection<T> c) {...}
}
Without special dispensation, Overrider.toList would no longer override CollectionConverter.toList. Instead, the code would be illegal. This would significantly inhibit the use of generics, since library writers would hesitate to migrate existing code.
Best Answer
Applying from array is literally applying from an array, not from a style object
or alternatively: