Python – Asserting successive calls to a mock method

mockingpython

Mock has a helpful assert_called_with() method. However, as far as I understand this only checks the last call to a method.
If I have code that calls the mocked method 3 times successively, each time with different parameters, how can I assert these 3 calls with their specific parameters?

Best Answer

assert_has_calls is another approach to this problem.

From the docs:

assert_has_calls (calls, any_order=False)

assert the mock has been called with the specified calls. The mock_calls list is checked for the calls.

If any_order is False (the default) then the calls must be sequential. There can be extra calls before or after the specified calls.

If any_order is True then the calls can be in any order, but they must all appear in mock_calls.

Example:

>>> from unittest.mock import call, Mock
>>> mock = Mock(return_value=None)
>>> mock(1)
>>> mock(2)
>>> mock(3)
>>> mock(4)
>>> calls = [call(2), call(3)]
>>> mock.assert_has_calls(calls)
>>> calls = [call(4), call(2), call(3)]
>>> mock.assert_has_calls(calls, any_order=True)

Source: https://docs.python.org/3/library/unittest.mock.html#unittest.mock.Mock.assert_has_calls

Related Solutions

Python – “Least Astonishment” and the Mutable Default Argument

Actually, this is not a design flaw, and it is not because of internals or performance.
It comes simply from the fact that functions in Python are first-class objects, and not only a piece of code.

As soon as you think of it this way, then it completely makes sense: a function is an object being evaluated on its definition; default parameters are kind of "member data" and therefore their state may change from one call to the other - exactly as in any other object.

In any case, Effbot has a very nice explanation of the reasons for this behavior in Default Parameter Values in Python.
I found it very clear, and I really suggest reading it for a better knowledge of how function objects work.

Java – How to mock void methods with Mockito

Take a look at the Mockito API docs. As the linked document mentions (Point # 12) you can use any of the doThrow(),doAnswer(),doNothing(),doReturn() family of methods from Mockito framework to mock void methods.

For example,

Mockito.doThrow(new Exception()).when(instance).methodName();

or if you want to combine it with follow-up behavior,

Mockito.doThrow(new Exception()).doNothing().when(instance).methodName();

Presuming that you are looking at mocking the setter setState(String s) in the class World below is the code uses doAnswer method to mock the setState.

World mockWorld = mock(World.class); 
doAnswer(new Answer<Void>() {
    public Void answer(InvocationOnMock invocation) {
      Object[] args = invocation.getArguments();
      System.out.println("called with arguments: " + Arrays.toString(args));
      return null;
    }
}).when(mockWorld).setState(anyString());

Best Answer

Related Solutions

Python – “Least Astonishment” and the Mutable Default Argument

Java – How to mock void methods with Mockito

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