Python – Changing pixel color value in PIL

pythonpython-imaging-library

I need to change pixel color of an image in python. Except for the pixel value (255, 0, 0) red I need to change every pixel color value into black (0, 0, 0). I tried the following code but it doesn't helped.

from PIL import Image
im = Image.open('A:\ex1.jpg')
for pixel in im.getdata():
    if pixel == (255,0,0):
        print "Red coloured pixel"
    else:
        pixel = [0, 0, 0]

Best Answer

See this wikibook: https://en.wikibooks.org/wiki/Python_Imaging_Library/Editing_Pixels

Modifying that code to fit your problem:

pixels = img.load() # create the pixel map

for i in range(img.size[0]): # for every pixel:
    for j in range(img.size[1]):
        if pixels[i,j] != (255, 0, 0):
            # change to black if not red
            pixels[i,j] = (0, 0 ,0)

Related Solutions

Python – How to sort a list of dictionaries by a value of the dictionary

The sorted() function takes a key= parameter

newlist = sorted(list_to_be_sorted, key=lambda d: d['name'])

Alternatively, you can use operator.itemgetter instead of defining the function yourself

from operator import itemgetter
newlist = sorted(list_to_be_sorted, key=itemgetter('name'))

For completeness, add reverse=True to sort in descending order

newlist = sorted(list_to_be_sorted, key=itemgetter('name'), reverse=True)

Python – How to sort a dictionary by value

Python 3.7+ or CPython 3.6

Dicts preserve insertion order in Python 3.7+. Same in CPython 3.6, but it's an implementation detail.

>>> x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
>>> {k: v for k, v in sorted(x.items(), key=lambda item: item[1])}
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

>>> dict(sorted(x.items(), key=lambda item: item[1]))
{0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

Older Python

It is not possible to sort a dictionary, only to get a representation of a dictionary that is sorted. Dictionaries are inherently orderless, but other types, such as lists and tuples, are not. So you need an ordered data type to represent sorted values, which will be a list—probably a list of tuples.

For instance,

import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(1))

sorted_x will be a list of tuples sorted by the second element in each tuple. dict(sorted_x) == x.

And for those wishing to sort on keys instead of values:

import operator
x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=operator.itemgetter(0))

In Python3 since unpacking is not allowed we can use

x = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0}
sorted_x = sorted(x.items(), key=lambda kv: kv[1])

If you want the output as a dict, you can use collections.OrderedDict:

import collections

sorted_dict = collections.OrderedDict(sorted_x)