Python – Import Error: No module named ‘utils’

fuzzywuzzyimporterrorpythonpython-3.xpython-import

Please excuse me I'm a newbie. I'm trying to use the fuzzywuzzy module from seatgeek. I am using Python 3

Initially, I was getting this error:

  from fuzzywuzzy import fuzz
ImportError: cannot import name fuzz

I changed the import statement to import fuzzywuzzy.fuzz and Now, I'm getting this error:

  File "test.py", line 4, in <module>
     import fuzzywuzzy.fuzz
  File "C:\Python33\lib\site-packages\fuzzywuzzy\fuzz.py", line 31, in <module>
     from utils import *
ImportError: No module named 'utils'

Best Answer

The fuzzywuzzy package is not Python 3 compatible, it'll only work on Python 2.

Specifically, the error is because the fuzz module uses relative imports, a technique removed from Python 3.

The repository issue tracker does have a Python 3 compatibility patch you could try out.

Related Solutions

Python – How to import a module given the full path

For Python 3.5+ use:

import importlib.util
spec = importlib.util.spec_from_file_location("module.name", "/path/to/file.py")
foo = importlib.util.module_from_spec(spec)
spec.loader.exec_module(foo)
foo.MyClass()

For Python 3.3 and 3.4 use:

from importlib.machinery import SourceFileLoader

foo = SourceFileLoader("module.name", "/path/to/file.py").load_module()
foo.MyClass()

(Although this has been deprecated in Python 3.4.)

For Python 2 use:

import imp

foo = imp.load_source('module.name', '/path/to/file.py')
foo.MyClass()

There are equivalent convenience functions for compiled Python files and DLLs.

Python – Import a module from a relative path

Assuming that both your directories are real Python packages (do have the __init__.py file inside them), here is a safe solution for inclusion of modules relatively to the location of the script.

I assume that you want to do this, because you need to include a set of modules with your script. I use this in production in several products and works in many special scenarios like: scripts called from another directory or executed with python execute instead of opening a new interpreter.

 import os, sys, inspect
 # realpath() will make your script run, even if you symlink it :)
 cmd_folder = os.path.realpath(os.path.abspath(os.path.split(inspect.getfile( inspect.currentframe() ))[0]))
 if cmd_folder not in sys.path:
     sys.path.insert(0, cmd_folder)

 # Use this if you want to include modules from a subfolder
 cmd_subfolder = os.path.realpath(os.path.abspath(os.path.join(os.path.split(inspect.getfile( inspect.currentframe() ))[0],"subfolder")))
 if cmd_subfolder not in sys.path:
     sys.path.insert(0, cmd_subfolder)

 # Info:
 # cmd_folder = os.path.dirname(os.path.abspath(__file__)) # DO NOT USE __file__ !!!
 # __file__ fails if the script is called in different ways on Windows.
 # __file__ fails if someone does os.chdir() before.
 # sys.argv[0] also fails, because it doesn't not always contains the path.

As a bonus, this approach does let you force Python to use your module instead of the ones installed on the system.

Warning! I don't really know what is happening when current module is inside an egg file. It probably fails too.

Best Answer

Related Solutions

Python – How to import a module given the full path

Python – Import a module from a relative path

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