Python – mod_wsgi on Snow Leopard python version mismatch

apachemakefilemod-wsgipython

I'm trying to run mod_wsgi 3.1 under Apache 2.2.14 using a non-default python installation on Mac OS X 10.6.

After downloading the mod_wsgi source I run:

sudo apachectl -k stop

then

./configure --with-python=/usr/local/Cellar/python/2.6.4/bin/python
make
sudo make install

I then start up apache again

sudo apachectl -k start

When I cat /var/log/httpd/error_log I see:

[Mon Dec 21 12:27:26 2009] [warn] mod_wsgi: Compiled for Python/2.6.4.

[Mon Dec 21 12:27:26 2009] [warn] mod_wsgi: Runtime using Python/2.6.1.

[Mon Dec 21 12:27:26 2009] [notice] Apache/2.2.14 (Unix) DAV/2 mod_wsgi/3.1 Python/2.6.1 configured — resuming normal operations

When I run otool -L mod_wsgi.so is see:

mod_wsgi.so:

/System/Library/Frameworks/Python.framework/Versions/2.6/Python (compatibility version 2.6.0, current version 2.6.1)

/usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 125.0.0)

What gives? Why is it linking with the system framework?

Here is the output from my mod_wsgi configure and build commands:


Archimedes:mod_wsgi-3.1 awolf$ ./configure –with-python=/usr/local/Cellar/python/2.6.4/bin/python

checking for apxs2… no

checking for apxs… /opt/apache2/bin/apxs

checking Apache version… 2.2.14

configure: creating ./config.status

config.status: creating Makefile

Archimedes:mod_wsgi-3.1 awolf$ make

/opt/apache2/bin/apxs -c -I/usr/local/Cellar/python/2.6.4/include/python2.6 -DNDEBUG -Wc,'-arch x86_64' mod_wsgi.c -L/usr/local/Cellar/python/2.6.4/lib -L/usr/local/Cellar/python/2.6.4/lib/python2.6/config -arch x86_64 -lpython2.6 -ldl
/Library/Webserver/build/libtool –silent –mode=compile gcc -prefer-pic -DDARWIN -DSIGPROCMASK_SETS_THREAD_MASK -no-cpp-precomp -g -O2 -I/opt/apache2/include -I/opt/apache2/include -I/opt/apache2/include -arch x86_64 -I/usr/local/Cellar/python/2.6.4/include/python2.6 -DNDEBUG -c -o mod_wsgi.lo mod_wsgi.c && touch mod_wsgi.slo

In file included from /usr/local/Cellar/python/2.6.4/include/python2.6/Python.h:125,

             from mod_wsgi.c:135:

/usr/local/Cellar/python/2.6.4/include/python2.6/modsupport.h:27: warning: 'PyArg_ParseTuple' is an unrecognized format function type
/Library/Webserver/build/libtool –silent –mode=link gcc -o mod_wsgi.la -rpath /opt/apache2/modules -module -avoid-version mod_wsgi.lo -L/usr/local/Cellar/python/2.6.4/lib -L/usr/local/Cellar/python/2.6.4/lib/python2.6/config -arch x86_64 -lpython2.6 -ldl

Archimedes:mod_wsgi-3.1 awolf$ sudo make install

Password:

/opt/apache2/bin/apxs -i -S LIBEXECDIR=/opt/apache2/modules -n 'mod_wsgi' mod_wsgi.la

/Library/Webserver/build/instdso.sh SH_LIBTOOL='/Library/Webserver/build/libtool' mod_wsgi.la /opt/apache2/modules

/Library/Webserver/build/libtool –mode=install cp mod_wsgi.la /opt/apache2/modules/

cp .libs/mod_wsgi.so /opt/apache2/modules/mod_wsgi.so

cp .libs/mod_wsgi.lai /opt/apache2/modules/mod_wsgi.la

cp .libs/mod_wsgi.a /opt/apache2/modules/mod_wsgi.a

chmod 644 /opt/apache2/modules/mod_wsgi.a

ranlib /opt/apache2/modules/mod_wsgi.a

Best Answer

This post is old, but still turns up in searches about mac + homebrew + python, so I thought I'd add some useful information. I was having the problem as the OP, just with a different module (uwsgi). I learned that you don't have to abandon homebrew. Homebrew can, in fact, install python as a framework; you just have to tell it to do so:

% brew uninstall python
Uninstalling /usr/local/Cellar/python/2.7.2...
% brew install python --universal --framework

... and all's well.