Python – Replace special characters with ASCII equivalent

pythonunicode

Is there any lib that can replace special characters to ASCII equivalents, like:

"Cześć"

to:

"Czesc"

I can of course create map:

{'ś':'s', 'ć': 'c'}

and use some replace function. But I don't want to hardcode all equivalents into my program, if there is some function that already does that.

Best Answer

#!/usr/bin/env python
# -*- coding: utf-8 -*-

import unicodedata
text = u'Cześć'
print unicodedata.normalize('NFD', text).encode('ascii', 'ignore')

Related Solutions

Python – Proper way to declare custom exceptions in modern Python

Maybe I missed the question, but why not:

class MyException(Exception):
    pass

To override something (or pass extra args), do this:

class ValidationError(Exception):
    def __init__(self, message, errors):            
        # Call the base class constructor with the parameters it needs
        super().__init__(message)
            
        # Now for your custom code...
        self.errors = errors

That way you could pass dict of error messages to the second param, and get to it later with e.errors.

In Python 2, you have to use this slightly more complex form of super():

super(ValidationError, self).__init__(message)

Regex – (grep) Regex to match non-ASCII characters

This will match a single non-ASCII character:

[^\x00-\x7F]

This is a valid PCRE (Perl-Compatible Regular Expression).

You can also use the POSIX shorthands:

[[:ascii:]] - matches a single ASCII char
[^[:ascii:]] - matches a single non-ASCII char

[^[:print:]] will probably suffice for you.**

Best Answer

Related Solutions

Python – Proper way to declare custom exceptions in modern Python

Regex – (grep) Regex to match non-ASCII characters

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