Python – subprocess.check_output return code

pythonsubprocess

I am using:

grepOut = subprocess.check_output("grep " + search + " tmp", shell=True)

To run a terminal command, I know that I can use a try/except to catch the error but how can I get the value of the error code?

I found this on the official documentation:

 exception subprocess.CalledProcessError

    Exception raised when a process run by check_call() or check_output() returns a non-zero exit status.

    returncode

        Exit status of the child process.

But there are no examples given and Google was of no help.

Best Answer

You can get the error code and results from the exception that is raised.

This can be done through the fields returncode and output.

For example:

import subprocess

try:
    grepOut = subprocess.check_output("grep " + "test" + " tmp", shell=True)                       
except subprocess.CalledProcessError as grepexc:                                                                                                   
    print("error code", grepexc.returncode, grepexc.output)
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