Python /usr/bin/env: bad interpreter: Not a directory

bashlinuxpython

I did a mistake. I installed Python 3 and then I did the following command in order to have the defaut version Python as Python3

sudo ln -fs /opt/Python-3.4.1/python /usr/bin/python

But I wanted to come back to the python2.7 and I did

sudo ln -fs /usr/bin/python2.7/python /usr/bin/python

Now, When I want to run a bash script with python inside, I have this following error:

/usr/bin/env: bad interpreter: Not a directory

When I run this command:

ls -l /usr/bin/env

I have this result in red:

lrwxrwxrwx 1 root root 25 Jun 12 13:37 /usr/bin/env ->
/usr/bin/python2.7/python

Indeed, when I go in this directory, I don't have the env executable anymore but a broken link.

I didn't find a solution on the internet.

Could you help me ? I begin to feel bad about my mistake.

Thanks

Best Answer

Okey, I solved my issue by reinstalling this env file.

sudo apt-get install --reinstall coreutils

Then thanks to this post in Why do people write the #!/usr/bin/env python shebang on the first line of a Python script? I know better how to switch between version and do not do the same mistake anymore.

Related Solutions

Python – Why do people write #!/usr/bin/env python on the first line of a Python script

If you have several versions of Python installed, /usr/bin/env will ensure the interpreter used is the first one on your environment's $PATH. The alternative would be to hardcode something like #!/usr/bin/python; that's ok, but less flexible.

In Unix, an executable file that's meant to be interpreted can indicate what interpreter to use by having a #! at the start of the first line, followed by the interpreter (and any flags it may need).

If you're talking about other platforms, of course, this rule does not apply (but that "shebang line" does no harm, and will help if you ever copy that script to a platform with a Unix base, such as Linux, Mac, etc).

Python – How to find if directory exists in Python

You're looking for os.path.isdir, or os.path.exists if you don't care whether it's a file or a directory:

>>> import os
>>> os.path.isdir('new_folder')
True
>>> os.path.exists(os.path.join(os.getcwd(), 'new_folder', 'file.txt'))
False

Alternatively, you can use pathlib:

 >>> from pathlib import Path
 >>> Path('new_folder').is_dir()
 True
 >>> (Path.cwd() / 'new_folder' / 'file.txt').exists()
 False

Best Answer

Related Solutions

Python – Why do people write #!/usr/bin/env python on the first line of a Python script

Python – How to find if directory exists in Python

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