Variables declared inside the class definition, but not inside a method are class or static variables:
>>> class MyClass:
... i = 3
...
>>> MyClass.i
3
As @millerdev points out, this creates a class-level i
variable, but this is distinct from any instance-level i
variable, so you could have
>>> m = MyClass()
>>> m.i = 4
>>> MyClass.i, m.i
>>> (3, 4)
This is different from C++ and Java, but not so different from C#, where a static member can't be accessed using a reference to an instance.
See what the Python tutorial has to say on the subject of classes and class objects.
@Steve Johnson has already answered regarding static methods, also documented under "Built-in Functions" in the Python Library Reference.
class C:
@staticmethod
def f(arg1, arg2, ...): ...
@beidy recommends classmethods over staticmethod, as the method then receives the class type as the first argument, but I'm still a little fuzzy on the advantages of this approach over staticmethod. If you are too, then it probably doesn't matter.
A lambda is just an anonymous function - a function defined with no name. In some languages, such as Scheme, they are equivalent to named functions. In fact, the function definition is re-written as binding a lambda to a variable internally. In other languages, like Python, there are some (rather needless) distinctions between them, but they behave the same way otherwise.
A closure is any function which closes over the environment in which it was defined. This means that it can access variables not in its parameter list. Examples:
def func(): return h
def anotherfunc(h):
return func()
This will cause an error, because func
does not close over the environment in anotherfunc
- h
is undefined. func
only closes over the global environment. This will work:
def anotherfunc(h):
def func(): return h
return func()
Because here, func
is defined in anotherfunc
, and in python 2.3 and greater (or some number like this) when they almost got closures correct (mutation still doesn't work), this means that it closes over anotherfunc
's environment and can access variables inside of it. In Python 3.1+, mutation works too when using the nonlocal
keyword.
Another important point - func
will continue to close over anotherfunc
's environment even when it's no longer being evaluated in anotherfunc
. This code will also work:
def anotherfunc(h):
def func(): return h
return func
print anotherfunc(10)()
This will print 10.
This, as you notice, has nothing to do with lambdas - they are two different (although related) concepts.
Best Answer
For the simple case, you're better off using a map.
If you really do want to evaluate it as a closure (possibly to create your own DSL), you'll need to change your syntax slightly as John points out. Here's one way to do it using a Builder class to evaluate the "something" closure within whatever is passed to the builder.
It uses groovy metaprogramming to intercept calls with method/property missing and to save them off: