Delphi – Are delphi variables initialized with a value by default

delphiinitializationvariables

I'm new to Delphi, and I've been running some tests to see what object variables and stack variables are initialized to by default:

TInstanceVariables = class
  fBoolean: boolean; // always starts off as false
  fInteger: integer; // always starts off as zero
  fObject: TObject; // always starts off as nil
end;

This is the behaviour I'm used to from other languages, but I'm wondering if it's safe to rely on it in Delphi? For example, I'm wondering if it might depend on a compiler setting, or perhaps work differently on different machines. Is it normal to rely on default initialized values for objects, or do you explicitly set all instance variables in the constructor?

As for stack (procedure-level) variables, my tests are showing that unitialized booleans are true, unitialized integers are 2129993264, and uninialized objects are just invalid pointers (i.e. not nil). I'm guessing the norm is to always set procedure-level variables before accessing them?

Best Answer

Yes, this is the documented behaviour:

Object fields are always initialized to 0, 0.0, '', False, nil or whatever applies.
Global variables are always initialized to 0 etc as well;
Local reference-counted* variables are always initialized to nil or '';
Local non reference-counted* variables are uninitialized so you have to assign a value before you can use them.

I remember that Barry Kelly somewhere wrote a definition for "reference-counted", but cannot find it any more, so this should do in the meantime:

reference-counted == that are reference-counted themselves, or directly or indirectly contain fields (for records) or elements (for arrays) that are reference-counted like: string, variant, interface or dynamic array or static array containing such types.

Notes:

record itself is not enough to become reference-counted
I have not tried this with generics yet

Related Solutions

Php – Are PHP Variables passed by value or by reference

It's by value according to the PHP Documentation.

By default, function arguments are passed by value (so that if the value of the argument within the function is changed, it does not get changed outside of the function). To allow a function to modify its arguments, they must be passed by reference.

To have an argument to a function always passed by reference, prepend an ampersand (&) to the argument name in the function definition.

<?php
function add_some_extra(&$string)
{
    $string .= 'and something extra.';
}

$str = 'This is a string, ';
add_some_extra($str);
echo $str;    // outputs 'This is a string, and something extra.'
?>

Java – Why are local variables not initialized in Java

Local variables are declared mostly to do some calculation. So it's the programmer's decision to set the value of the variable and it should not take a default value.

If the programmer, by mistake, did not initialize a local variable and it takes a default value, then the output could be some unexpected value. So in case of local variables, the compiler will ask the programmer to initialize it with some value before they access the variable to avoid the usage of undefined values.

Best Answer

Related Solutions

Php – Are PHP Variables passed by value or by reference

Java – Why are local variables not initialized in Java

Related Topic