R – grep and sed – replace all instances of a string

bashgrepsed

I have a bash script I'm writing that greps for a filepath. I want to be able to use the output of the grep to replace each instance of the old filepath with the new filepath.

Example:

grep -R "/~test/dev/portal" .

I want to be able to pipe this output into sed to replace each instance of "/~test/dev/portal/" with "/apps/portal/" (keep in mind, the output of the grep is typically more than one file)

Thanks in advance!

Best Answer

grep -ZlR "/~test/dev/portal" . | xargs -0 -l1 sed -i 's:/~test/dev/portal/:/apps/portal/:g'

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Linux – Get program execution time in the shell

Use the built-in time keyword:

$ help time

time: time [-p] PIPELINE
    Execute PIPELINE and print a summary of the real time, user CPU time,
    and system CPU time spent executing PIPELINE when it terminates.
    The return status is the return status of PIPELINE.  The `-p' option
    prints the timing summary in a slightly different format.  This uses
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Example:

$ time sleep 2

real    0m2.009s
user    0m0.000s
sys     0m0.004s

How to replace a newline (\n) using sed

sed is intended to be used on line-based input. Although it can do what you need.

A better option here is to use the tr command as follows:

tr '\n' ' ' < input_filename

or remove the newline characters entirely:

tr -d '\n' < input.txt > output.txt

or if you have the GNU version (with its long options)

tr --delete '\n' < input.txt > output.txt

Best Answer

Related Solutions

Linux – Get program execution time in the shell

How to replace a newline (\n) using sed

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