How to add a “sleep” or “wait” to the Lua Script

luasleeptimerwait

I'm trying to make a simple script for a game, by changing the time of day, but I want to do it in a fast motion. So this is what I'm talking about:

function disco ( hour, minute)
setTime ( 1, 0 )
SLEEP
setTime ( 2, 0 )
SLEEP
setTime ( 3, 0 )
end

and so on. How would I go about doing this?

Best Answer

Lua doesn't provide a standard sleep function, but there are several ways to implement one, see Sleep Function for detail.

For Linux, this may be the easiest one:

function sleep(n)
  os.execute("sleep " .. tonumber(n))
end

In Windows, you can use ping:

function sleep(n)
  if n > 0 then os.execute("ping -n " .. tonumber(n+1) .. " localhost > NUL") end
end

The one using select deserves some attention because it is the only portable way to get sub-second resolution:

require "socket"

function sleep(sec)
    socket.select(nil, nil, sec)
end

sleep(0.2)

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Use time.sleep()

from time import sleep
sleep(0.05)

Python – the best way to repeatedly execute a function every x seconds?

If your program doesn't have a event loop already, use the sched module, which implements a general purpose event scheduler.

import sched, time
s = sched.scheduler(time.time, time.sleep)
def do_something(sc): 
    print("Doing stuff...")
    # do your stuff
    s.enter(60, 1, do_something, (sc,))

s.enter(60, 1, do_something, (s,))
s.run()

If you're already using an event loop library like asyncio, trio, tkinter, PyQt5, gobject, kivy, and many others - just schedule the task using your existing event loop library's methods, instead.

Best Answer

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