Perl – How to do 64-bit arithmetic in Perl

64-bitperlsigned

I am a perl newbie,

Can I simply use 64-bit arithmetic in Perl?

For example

$operand1 = 0xFFFFFFFFFFFF;   # 48 bit value
$operand2 = 0xFFFFFFFFFFFF;   # 48 bit value

$Result = $operand1 * $operand2;

I am basically looking for a
replacement for the int64_t in perl.
Is there any way to mention, if the
variable is signed or unsigned?

Best Answer

Yes, however you need to have Perl compiled with 64-bit support.

Related Solutions

Regex – How to perform a Perl substitution on a string while keeping the original

This is the idiom I've always used to get a modified copy of a string without changing the original:

(my $newstring = $oldstring) =~ s/foo/bar/g;

In perl 5.14.0 or later, you can use the new /r non-destructive substitution modifier:

my $newstring = $oldstring =~ s/foo/bar/gr;

NOTE:
The above solutions work without g too. They also work with any other modifiers.

Signed versus Unsigned Integers

Unsigned can hold a larger positive value and no negative value.

Yes.

Unsigned uses the leading bit as a part of the value, while the signed version uses the left-most-bit to identify if the number is positive or negative.

There are different ways of representing signed integers. The easiest to visualise is to use the leftmost bit as a flag (sign and magnitude), but more common is two's complement. Both are in use in most modern microprocessors — floating point uses sign and magnitude, while integer arithmetic uses two's complement.

Signed integers can hold both positive and negative numbers.

Yes.

Best Answer

Related Solutions

Regex – How to perform a Perl substitution on a string while keeping the original

Signed versus Unsigned Integers

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