R- how to edit elements on x axis in image.plot

imager

I have created a image plot for this data:

sample
         p         p.1         p.2         p.3         p.4
  p    1.0000000  0.24077171 -0.66666667 -0.49009803  0.61237244
  p.1  0.2407717  1.00000000  0.09028939 -0.83444087  0.14744196
  p.2 -0.6666667  0.09028939  1.00000000  0.21004201  0.10206207
  p.3 -0.4900980 -0.83444087  0.21004201  1.00000000 -0.08574929
  p.4  0.6123724  0.14744196  0.10206207 -0.08574929  1.00000000

Using this code:

  image.plot(sample,col=redblue(191), zlim=c(-1,1))

I get this image:

Instead of 0.0 0.2 0.4.. on x and y axes, I want p p.1 p.2…
How do I get that that?
Thank you for your time and consideration?

My heatmap looks like this:

enter image description here

its not symmetric. Can you please fix this?
I am using this code:

shades=c(seq(-1,-0.5,length=64), seq(-0.5,0.5, length=64), seq(0.5,1,length=64))
heatmap.2(sample, dendrogram='none', symm=TRUE, Rowv=FALSE, Colv=FALSE, key=TRUE, cexCol=0.7, cexRow=1,scale="row", keysize=1, col=redblue(191), breaks=shades)

Best Answer

Here is a better-ish solution:

 par(mar=c(5,4.5,4,7))
 image(sample, col=rainbow(25), axes=F)  #redblue() doesn't work on my computer.
 axis(2)
 axis(1, at=seq(0,0.8,0.2), labels=rownames(sample))
 image.plot(sample, legend.only=T)

enter image description here

EDIT: Does the plot below look like what you are looking for?

 sample = cor(matrix(rnorm(400), nrow=20))
 image(cor(matrix(rnorm(400), nrow=20)), axes=F)
 mtext(text=c(paste("country",1:21)), side=2, line=0.3, at=seq(0,1,0.05), las=1, cex=0.8)
 mtext(text=c(paste("country",1:21)), side=1, line=0.3, at=seq(0,1,0.05), las=2, cex=0.8)
 image.plot(sample, legend.only=T)

enter image description here

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package com.wilson.android.library;

/*
 Licensed to the Apache Software Foundation (ASF) under one or more
contributor license agreements.  See the NOTICE file
distributed with this work for additional information
regarding copyright ownership.  The ASF licenses this file
to you under the Apache License, Version 2.0 (the
"License"); you may not use this file except in compliance
with the License.  You may obtain a copy of the License at

http://www.apache.org/licenses/LICENSE-2.0

Unless required by applicable law or agreed to in writing,
software distributed under the License is distributed on an
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KIND, either express or implied.  See the License for the
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You can use the order() function directly without resorting to add-on tools -- see this simpler answer which uses a trick right from the top of the example(order) code:

R> dd[with(dd, order(-z, b)), ]
    b x y z
4 Low C 9 2
2 Med D 3 1
1  Hi A 8 1
3  Hi A 9 1

Edit some 2+ years later: It was just asked how to do this by column index. The answer is to simply pass the desired sorting column(s) to the order() function:

R> dd[order(-dd[,4], dd[,1]), ]
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4 Low C 9 2
2 Med D 3 1
1  Hi A 8 1
3  Hi A 9 1
R>

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